Math Problem Statement

You are climbing in the High Sierra when you suddenly find yourself at the edge of a fog-shrouded cliff. To find the height of this cliff, you drop a rock from the top; 8.20 s later you hear the sound of the rock hitting the ground at the foot of the cliff. If you ignore air resistance, how high is the cliff if the speed of sound is 330 m/s ?

Solution

To find the height of the cliff, we'll break the problem into two parts:

  1. Time taken by the rock to fall from the top of the cliff to the bottom.
  2. Time taken by the sound to travel back up from the bottom to the top.

Given:

  • Total time for the rock to fall and the sound to travel back: ttotal=8.20t_{\text{total}} = 8.20 seconds
  • Speed of sound: vsound=330v_{\text{sound}} = 330 m/s
  • Acceleration due to gravity: g=9.81g = 9.81 m/s²

Step 1: Define the unknowns

Let:

  • hh be the height of the cliff.
  • t1t_1 be the time it takes for the rock to fall.
  • t2t_2 be the time it takes for the sound to travel back up.

From the total time: ttotal=t1+t2t_{\text{total}} = t_1 + t_2 t2=hvsoundt_2 = \frac{h}{v_{\text{sound}}} t1+h330=8.20t_1 + \frac{h}{330} = 8.20

Step 2: Use the equation of motion for the rock's fall

The distance fallen by the rock is given by: h=12gt12h = \frac{1}{2} g t_1^2 h=12×9.81×t12h = \frac{1}{2} \times 9.81 \times t_1^2

Step 3: Substitute t2t_2 into the total time equation

Substituting hh from the rock’s fall equation into the sound travel time equation: t1+12×9.81×t12330=8.20t_1 + \frac{\frac{1}{2} \times 9.81 \times t_1^2}{330} = 8.20

Step 4: Solve for t1t_1 and then find hh

We have the equation: t1+4.905×t12330=8.20t_1 + \frac{4.905 \times t_1^2}{330} = 8.20 This equation can be solved using algebraic or numerical methods.

Let's calculate t1t_1 and then use it to find hh.

We can solve this equation using Python.The two solutions for t1t_1 (the time it takes for the rock to fall) are approximately:

  • t174.67t_1 \approx -74.67 seconds (not physically meaningful since time cannot be negative)
  • t17.39t_1 \approx 7.39 seconds

So, t1=7.39t_1 = 7.39 seconds is the valid solution.

Step 5: Calculate the height of the cliff hh

Now that we have t1t_1, we can calculate the height hh using the formula: h=12gt12h = \frac{1}{2} g t_1^2 Let's calculate hh.The height of the cliff is approximately 267.77267.77 meters.

Would you like more details, or do you have any questions? Here are a few related questions you might find interesting:

  1. How would the height change if the speed of sound was different?
  2. How would air resistance affect the time taken for the rock to fall?
  3. What would be the height if the total time was 10 seconds instead of 8.20 seconds?
  4. Can you derive a general formula for the height in terms of total time and speed of sound?
  5. How would the height calculation differ on another planet with different gravity?

Tip: Always double-check the units in physics problems to ensure accuracy.

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Math Problem Analysis

Mathematical Concepts

Kinematics
Projectile Motion
Speed of Sound

Formulas

Distance traveled under constant acceleration
Sound travel time formula

Theorems

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Suitable Grade Level

High School

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