A lightning bolt with 10 kA strikes an object for 15micro s.
How much charge is deposited on the object?

To calculate the charge deposited on the object by the lightning bolt, we can use the relationship between current (\(I\)), charge (\(Q\)), and time (\(t\)). The formula is:

\[
Q = I \times t
\]

Where:
- \(I\) is the current in amperes (A).
- \(t\) is the time in seconds (s).
- \(Q\) is the charge in coulombs (C).

Given:
- \(I = 10 \text{ kA} = 10 \times 10^3 \text{ A}\)
- \(t = 15 \text{ microseconds} = 15 \times 10^{-6} \text{ s}\)

Now, we can calculate the charge \(Q\):

\[
Q = 10 \times 10^3 \text{ A} \times 15 \times 10^{-6} \text{ s} 
\]

\[
Q = 150 \text{ C}
\]

So, **150 coulombs** of charge is deposited on the object.

Would you like more details or have any questions?

Here are 5 related questions you might find interesting:
1. What is the energy transferred by the lightning if the voltage is known?
2. How does the time duration of the current affect the charge deposited?
3. What would happen if the current were doubled while keeping the time constant?
4. How does the deposited charge impact the object?
5. How do you convert between microseconds and seconds?

**Tip:** Remember that 1 microsecond (μs) is \(10^{-6}\) seconds, a key conversion in timing calculations.

Learn how to calculate the charge deposited on an object by a lightning bolt with 10 kA current for 15 microseconds. Understand the relationship between current, time, and charge using the formula Q = I * t. Suitable for advanced high school students and anyone interested in electrical calculations.

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