Math Problem Statement
Solution
Let's break down the problem and solve it step-by-step.
Given:
- Initial value of the car in 1993 = $26,000
- Value of the car in 2006 = $14,000
- Time period = 2006 - 1993 = 13 years
We assume the depreciation follows an exponential decay model: Where:
- is the value of the car after time ,
- is the initial value,
- is the annual rate of depreciation,
- is the time in years.
For part (A), we need to find (the rate of depreciation).
Step 1: Using the exponential decay model
We know:
Divide both sides by 26,000:
Step 2: Solve for
To solve for , take the 13th root of both sides:
Now calculate the right-hand side.
The annual rate of decrease is approximately 0.0465 (rounded to four decimal places).
Part A:
Part B: Convert to percentage form:
To express as a percentage, multiply by 100:
Part B:
Part C: Predicting the value in 2009
Using the same formula, we can predict the value of the car in 2009 (16 years after 1993). The formula is:
Let's calculate the value in 2009.
Part C:
The estimated value of the car in 2009 is approximately $12,150, rounded to the nearest 50 dollars.
Let me know if you would like further details on any part of this solution.
Here are 5 related questions to explore:
- How would the calculation change if the car's value dropped at a different rate every year?
- What is the total depreciation amount from 1993 to 2006?
- Can you derive the value of the car in a different year, say 2010, using the same formula?
- What is the compound annual growth rate (CAGR) formula and how is it related to the formula used here?
- How would inflation affect the real value of the car over this period?
Tip: Always ensure to apply the correct time period when using exponential growth or decay models for financial calculations.
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Math Problem Analysis
Mathematical Concepts
Exponential Decay
Algebra
Percentage
Formulas
Exponential decay formula: V(t) = V_0 * (1 - r)^t
Percentage calculation: r * 100
Theorems
-
Suitable Grade Level
Grades 9-12
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