The speed of a car decreases uniformly from 46 m/s to 9 m/s in a time interval of 9 seconds.  What is the magnitude of the car's acceleration?  Round to the tenths place (one digit after the decimal). *Numeric value ONLY. Do Not add m/s2.*

# To solve this problem, we'll use the formula for acceleration:
# acceleration (a) = (final velocity - initial velocity) / time
# Given:
initial_velocity = 46  # m/s
final_velocity = 9  # m/s
time_interval = 9  # seconds

# Calculating acceleration
acceleration = (final_velocity - initial_velocity) / time_interval
rounded_acceleration = round(abs(acceleration), 1)
rounded_acceleration4.1 

Would you like more details or have any questions? Here are 5 related questions you might find interesting:

1. What is the direction of acceleration in this scenario?
2. How do you determine if acceleration is positive or negative?
3. What would the final velocity be if the time interval was doubled?
4. How would you calculate the distance traveled during this deceleration?
5. How can you determine if the car comes to a complete stop?

**Tip:** When dealing with deceleration, remember that the acceleration value will be negative, but magnitude is always positive.

The speed of a car decreases uniformly from 46 m/s to 9 m/s in a time interval of 9 seconds. What is the magnitude of the car's acceleration? Round to the tenths place (one digit after the decimal).

Learn how to calculate the magnitude of a car's acceleration as it slows down uniformly from 46 m/s to 9 m/s over a 9-second interval. This problem applies kinematic concepts and the first equation of motion, making it suitable for students in Grades 9-11.

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