Math Problem Statement

Consider the exponential function shown here. Point A is at (−3;−5) and Point B is at (−1;52) , as shown.

What is the average gradient of g between the points?

Answer: The average gradient is

Solution

To find the average gradient (or average rate of change) of the function g(x)g(x) between the points A(3,5)A(-3, -5) and B(1,52)B(-1, 52), we use the following formula for the average gradient between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) on a function:

Average Gradient=y2y1x2x1\text{Average Gradient} = \frac{y_2 - y_1}{x_2 - x_1}

Substituting the coordinates of points AA and BB:

Average Gradient=52(5)1(3)\text{Average Gradient} = \frac{52 - (-5)}{-1 - (-3)}

Now, simplify the expression:

Average Gradient=52+51+3=572=28.5\text{Average Gradient} = \frac{52 + 5}{-1 + 3} = \frac{57}{2} = 28.5

So, the average gradient of g(x)g(x) between the points A(3,5)A(-3, -5) and B(1,52)B(-1, 52) is 28.528.5.

Would you like more details, or do you have any questions?

Here are 5 related questions:

  1. What is the gradient of the function g(x)g(x) at a specific point, such as x=2x = -2?
  2. How would you find the equation of the tangent to the curve g(x)g(x) at point BB?
  3. What is the significance of the gradient in the context of an exponential function?
  4. How does the gradient change as xx increases for an exponential function?
  5. How do you calculate the instantaneous rate of change for g(x)g(x) at a particular point?

Tip: When calculating the average gradient, ensure that you correctly subtract the coordinates in the right order to avoid sign errors.

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Math Problem Analysis

Mathematical Concepts

Exponential Functions
Average Gradient
Rate of Change

Formulas

Average Gradient formula: (y2 - y1) / (x2 - x1)

Theorems

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Suitable Grade Level

Grades 10-12