Math Problem Statement
A person jumps from the roof of a house 3.6-m high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.66 m . v=8.4 m/s. If the mass of his torso (excluding legs) is 41 kg , find the magnitude of the average force exerted on his torso by his legs during deceleration.
Solution
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Math Problem Analysis
Mathematical Concepts
Kinematics
Newton's Second Law of Motion
Deceleration
Formulas
v_f^2 = v_i^2 + 2ad
a = (v_f^2 - v_i^2) / (2d)
F = ma
Theorems
Newton's Second Law
Suitable Grade Level
Grades 11-12
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