Assume that an intercontinental ballistic missile goes from rest to a suborbital speed of 6.3km/s in 55s.(the actual speed and time are classified). What is its average acceleration in multiples of g (9.80 m/s2)? Express just the multiple.

To find the missile's average acceleration in multiples of \( g \) (where \( g = 9.80 \, \text{m/s}^2 \)), follow these steps:

1. **Convert the speed from km/s to m/s:**

\[
6.3 \, \text{km/s} = 6300 \, \text{m/s}
\]

2. **Calculate the acceleration:**

\[
a = \frac{\Delta v}{\Delta t} = \frac{6300 \, \text{m/s}}{55 \, \text{s}} \approx 114.55 \, \text{m/s}^2
\]

3. **Express this acceleration as a multiple of \( g \):**

\[
\text{Multiple of } g = \frac{114.55 \, \text{m/s}^2}{9.80 \, \text{m/s}^2} \approx 11.69
\]

So, the missile's average acceleration is approximately **11.69** times the acceleration due to gravity \( g \).

Would you like further details or have any questions?

Here are some related questions:
1. How does this acceleration compare to that of other vehicles, like fighter jets?
2. What would be the missile's speed after 30 seconds?
3. How far would the missile travel during this acceleration period?
4. How does this acceleration impact the structure of the missile?
5. How does this acceleration relate to the forces experienced by the payload?

**Tip:** When working with very large or very small values, always check unit conversions to maintain accuracy.

Learn how to calculate the average acceleration of an intercontinental ballistic missile from rest to 6.3 km/s in 55 seconds. This problem involves converting units, applying the average acceleration formula, and expressing acceleration in multiples of g (9.80 m/s²).

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