To find the average acceleration, we can use the basic formula of acceleration:

$a = \frac{{\Delta v}}{{\Delta t}}$

where:

• $\Delta v$ is the change in velocity,
• $\Delta t$ is the time interval.

Given:

• $\Delta v = 6.50 \, \text{km/s} = 6500 \, \text{m/s}$,
• $\Delta t = 60.0 \, \text{s}$.

Step 1: Calculate the average acceleration in $\text{m/s}^2$

$a = \frac{6500 \, \text{m/s}}{60.0 \, \text{s}} = 108.33 \, \text{m/s}^2$

Step 2: Convert the acceleration into multiples of $g$ ($g = 9.80 \, \text{m/s}^2$)

$a_{\text{multiples of g}} = \frac{a}{g} = \frac{108.33 \, \text{m/s}^2}{9.80 \, \text{m/s}^2} = 11.05 \, g$

Final Results:

• Average acceleration: $108.33 \, \text{m/s}^2$,
• In multiples of $g$: $11.05 \, g$.

Would you like any further explanation or details? Here are some related questions to explore:

1. What is the difference between average acceleration and instantaneous acceleration?
2. How would the calculation change if air resistance were considered?
3. What is the maximum velocity for a typical intercontinental ballistic missile (ICBM)?
4. How does this acceleration compare to that of a spacecraft during launch?
5. What physical effects would 11 g of acceleration have on humans?

Tip: Always convert units to SI units before performing calculations to avoid errors.