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I see the image you uploaded. Let's go over the problem step-by-step:

### Problem 1:
The container has a height of 35 cm and a cross-section designed from three semicircles with diameters of 17.5 cm, 6.5 cm, and 24 cm. Here are the tasks:

(a) **Calculate the area of the cross-section of the container.**

1. We need to find the areas of the semicircles and sum them up.
   - The area of a semicircle is given by \( A = \frac{1}{2} \pi r^2 \), where \( r \) is the radius.
   
   - For the first semicircle with a diameter of 17.5 cm:
     \[
     r_1 = \frac{17.5}{2} = 8.75 \, \text{cm}
     \]
     Area:
     \[
     A_1 = \frac{1}{2} \pi (8.75)^2
     \]

   - For the second semicircle with a diameter of 6.5 cm:
     \[
     r_2 = \frac{6.5}{2} = 3.25 \, \text{cm}
     \]
     Area:
     \[
     A_2 = \frac{1}{2} \pi (3.25)^2
     \]

   - For the third semicircle with a diameter of 24 cm:
     \[
     r_3 = \frac{24}{2} = 12 \, \text{cm}
     \]
     Area:
     \[
     A_3 = \frac{1}{2} \pi (12)^2
     \]

   The total area will be:
   \[
   A_{\text{total}} = A_1 + A_2 + A_3
   \]

(b) **Calculate the external surface area of the container, including the base.**

1. The surface area of a cylindrical container (without the top) can be calculated as:
   \[
   SA = \text{circumference of the base} \times \text{height} + \text{area of the base}
   \]
   Where the circumference is the perimeter of the cross-section (sum of the semicircle circumferences).

(c) **Calculate the capacity of the container.**
   
   The capacity (volume) of the container is given by:
   \[
   V = \text{Area of the cross-section} \times \text{height}
   \]
   The height is 35 cm, and the cross-sectional area was calculated in part (a). Convert the volume from cubic centimeters to liters (1 cm³ = 0.001 liters).

(d) **Pouring the water into a cone-shaped container.**
   
   The cone has a radius of 20 cm and a height of 40 cm. The volume of a cone is given by:
   \[
   V = \frac{1}{3} \pi r^2 h
   \]
   We will check if the water from the original container can fill this cone.

---

I will begin calculating each part now.The area of the cross-section of the container is approximately **363.05 cm²**.

Would you like me to continue with part (b), or do you have any questions on this so far?

Here are some related questions to deepen your understanding:
1. How would the calculation change if all three shapes were full circles instead of semicircles?
2. Can you think of how the shape of the container affects its overall surface area?
3. What impact does increasing the height of the container have on its capacity?
4. How could the shape of the base influence the structural stability of the container?
5. How would the material used for the container impact its external surface area?

**Tip:** Always double-check unit conversions when switching between cm² and liters!

Sandra has designed an open container with a height of 35 cm. The cross-section is designed from three semicircles with diameters of 17.5 cm, 6.5 cm, and 24 cm. Calculate the area of the cross-section, the external surface area including the base, the capacity in liters, and determine if the water from this container can fill another container shaped like a cone with a radius of 20 cm and height of 40 cm.

Learn how to calculate the area of a cross-section formed by three semicircles, the external surface area of an open container, its capacity in liters, and determine if it can fill a cone-shaped container. This problem involves geometry, surface area, volume calculation, and unit conversions, suitable for students in Grades 9-12.

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