The image depicts a triangle where:

• The base of the triangle is $19 \, \text{yd}$,
• The height (perpendicular from the base to the opposite vertex) is $7 \, \text{yd}$.

The formula to find the area $A$ of a triangle is:

$A = \frac{1}{2} \times \text{base} \times \text{height}$

Substituting the given values:

$A = \frac{1}{2} \times 19 \, \text{yd} \times 7 \, \text{yd}$ $A = \frac{1}{2} \times 133 \, \text{yd}^2 = 66.5 \, \text{yd}^2$

Thus, the area of the triangle is 66.5 square yards.

Would you like further details, or do you have any questions?

Here are some related questions:

1. How would the area change if the base was doubled?
2. What is the perimeter of the triangle given its sides?
3. Can you calculate the hypotenuse if this was a right triangle?
4. How does the area formula for a triangle relate to other shapes?
5. What if you only knew two sides and the angle between them—could you still find the area?

Tip: Always ensure the height used in the area calculation is perpendicular to the base!