To find the area enclosed by the square, we use the formula for the area of a square:

$\text{Area} = \text{side}^2$

In this problem, each side of the square is given as 7 cm. Plugging in this value:

$\text{Area} = 7^2 = 49 \, \text{cm}^2$

Answer:

The area enclosed by the square is $49 \, \text{cm}^2$.

Would you like additional details, or do you have any questions?

Here are some related questions for further practice:

1. If the side of a square is 10 cm, what is its area?
2. How would the area change if the side length of the square doubled?
3. What is the perimeter of a square with a side length of 7 cm?
4. How do you find the area of a square if only the diagonal length is known?
5. If the side length was in meters instead of centimeters, how would you convert the area to square centimeters?

Tip: Remember, the area of a square grows with the square of its side length, meaning that doubling the side length quadruples the area.