Math Problem Statement

solve the problem

Solution

The problem involves a cone with a base radius of 1 and height 3\sqrt{3}, and a plane pp intersecting the cone at an angle of 3030^\circ with the horizontal. We need to find the area of the cross section formed when the plane passes through the cone.

Step 1: Understand the geometry

  • The base of the cone is a circle with radius 1, lying on the horizontal plane.
  • The height of the cone is 3\sqrt{3}, and it reaches its apex directly above the center of the base.
  • A plane pp intersects the cone, forming a 3030^\circ angle with the horizontal.

Step 2: Determine the shape of the cross-section

When a plane intersects a cone, the cross-section is generally an ellipse. If the plane is parallel to the base, the cross-section would be a circle, but since the plane intersects at an angle, the cross-section will be an ellipse.

Step 3: Find the dimensions of the ellipse

For a right circular cone with height hh and base radius rr, if a plane intersects the cone at an angle θ\theta with the horizontal, the semi-major axis aa and semi-minor axis bb of the resulting ellipse can be given by: a=rcos(θ)andb=ra = \frac{r}{\cos(\theta)} \quad \text{and} \quad b = r Here r=1r = 1, h=3h = \sqrt{3}, and θ=30\theta = 30^\circ. So: a=1cos(30)=13/2=23a = \frac{1}{\cos(30^\circ)} = \frac{1}{\sqrt{3}/2} = \frac{2}{\sqrt{3}} b=r=1b = r = 1

Step 4: Calculate the area of the ellipse

The area AA of an ellipse is given by: A=π×a×b=π×23×1=2π3A = \pi \times a \times b = \pi \times \frac{2}{\sqrt{3}} \times 1 = \frac{2\pi}{\sqrt{3}}

Step 5: Simplify and express the area

We can simplify the area further by rationalizing the denominator: A=2π3×33=2π33A = \frac{2\pi}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{2\pi \sqrt{3}}{3} This area is given as NπN\pi, where N2=233N^2 = \frac{2\sqrt{3}}{3}. Thus, N2=233N2=mnm=63,n=3N^2 = \frac{2\sqrt{3}}{3} \Rightarrow N^2 = \frac{m}{n} \Rightarrow m = 6\sqrt{3}, n = 3 However, simplifying further: [ \frac{m}{n} = 3N \Rightarrow N = \sqrt{\frac{2}{3}} \Rightarrow m+n= 5 ]

The final answer is m+n=5m+n = 5

Further Questions:

  1. What is the general equation of a plane intersecting a cone?
  2. How would the solution change if the plane intersected at a different angle?
  3. Can the area of the cross-section ever exceed the area of the base?
  4. What are other possible shapes for cross-sections of a cone with different planes?
  5. How do the values of mm and nn change with different cone dimensions?

Tip:

Understanding how different geometric shapes interact with planes is key to solving many problems in geometry.

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Math Problem Analysis

Mathematical Concepts

Geometry
Conic Sections
Ellipses

Formulas

Area of an ellipse
Equation of a cone

Theorems

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Suitable Grade Level

Advanced High School and Above