Math Problem Statement

What is the area of this figure?

Enter your answer in the box.

A parallelogram with a right triangle created inside it with a short leg length of 5 m and a long leg length of 9 m. Two triangles attached to the top of the parallelogram are touching and share a long leg length of 8 m.

Solution

To find the area of the given figure, we must calculate the area of the parallelogram and adjust it by accounting for the additional and subtracted triangular areas.

Step 1: Identify Key Shapes

  1. Parallelogram:

    • A parallelogram's area is Aparallelogram=base×heightA_{\text{parallelogram}} = \text{base} \times \text{height}.
    • Here, the parallelogram's base is 9m9 \, \text{m} (long leg of the triangle), and the height is 5m5 \, \text{m} (short leg of the triangle).
    • Therefore: Aparallelogram=9×5=45m2.A_{\text{parallelogram}} = 9 \times 5 = 45 \, \text{m}^2.
  2. Additional Triangles:

    • Two triangles with base 8m8 \, \text{m} and shared height 5m5 \, \text{m} are attached to the top of the parallelogram.
    • The area of one triangle is: Atriangle=12×base×height=12×8×5=20m2.A_{\text{triangle}} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 8 \times 5 = 20 \, \text{m}^2.
    • Since there are two such triangles, their total area is: Aadded triangles=2×20=40m2.A_{\text{added triangles}} = 2 \times 20 = 40 \, \text{m}^2.
  3. Subtracted Triangle:

    • Inside the parallelogram is a right triangle with base 9m9 \, \text{m} and height 5m5 \, \text{m}.
    • Its area is: Asubtracted triangle=12×9×5=22.5m2.A_{\text{subtracted triangle}} = \frac{1}{2} \times 9 \times 5 = 22.5 \, \text{m}^2.

Step 2: Calculate the Total Area

Combine the areas: Atotal=Aparallelogram+Aadded trianglesAsubtracted triangle.A_{\text{total}} = A_{\text{parallelogram}} + A_{\text{added triangles}} - A_{\text{subtracted triangle}}. Substituting the values: Atotal=45+4022.5=62.5m2.A_{\text{total}} = 45 + 40 - 22.5 = 62.5 \, \text{m}^2.

Final Answer:

The area of the figure is: 62.5m2.\boxed{62.5 \, \text{m}^2}.


Would you like more details or have any questions?

Here are 5 related questions to deepen your understanding:

  1. How do you calculate the area of a parallelogram in general?
  2. Why is the formula for a triangle's area 12×base×height\frac{1}{2} \times \text{base} \times \text{height}?
  3. How would the area change if the attached triangles had different heights?
  4. What happens to the area of the parallelogram if one side is doubled?
  5. Can you determine the perimeter of the entire figure using the given dimensions?

Tip: When solving composite figure problems, always separate and analyze the individual shapes to avoid confusion!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Area Calculation
Composite Figures

Formulas

Area of a parallelogram: base × height
Area of a triangle: 1/2 × base × height

Theorems

Properties of Parallelograms
Area of Triangles

Suitable Grade Level

Grades 6-8