To find the percent of the total area under the standard normal curve between the z-scores $z = 0.7$ and $z = 1.3$, we can use the standard normal distribution table provided.

Step-by-Step Solution:

1. Look up $z = 0.7$ in the table:

   • From the image, the area for $z = 0.7$ is approximately 0.258.

2. Look up $z = 1.3$ in the table:

   • The area for $z = 1.3$ is approximately 0.403.

3. Calculate the area between $z = 0.7$ and $z = 1.3$:

   • Subtract the area at $z = 0.7$ from the area at $z = 1.3$: $0.403 - 0.258 = 0.145$

4. Convert to a percentage:

   • To express this area as a percentage, multiply by 100: $0.145 \times 100 = 14.5\%$

Answer:

The percent of the total area under the standard normal curve between $z = 0.7$ and $z = 1.3$ is 14.5%.

Would you like more details on any part of this calculation?

Here are some related questions to expand on this topic:

1. How do we interpret areas under the standard normal curve in probability terms?
2. What would be the area between other z-scores, such as $z = -0.5$ and $z = 1.5$?
3. How would we find the area if one of the z-scores was negative?
4. What is the significance of 0.5 in the standard normal table?
5. How does the area change as z-scores get closer to zero?

Tip: The total area under the standard normal curve is always 1 (or 100%), with half on each side of the mean (z = 0).