To find the percent of the total area under the standard normal curve between the z-scores $z = -1.4$ and $z = 0.65$, we can use the standard normal distribution table shown in your image.

Steps:

1. Find the area for $z = -1.4$: Using the first table (page 1), locate the z-score $z = -1.4$. The corresponding area is 0.0808.

2. Find the area for $z = 0.65$: Using the same table (page 1), locate the z-score $z = 0.65$. The corresponding area is 0.7422.

3. Subtract the two areas: To get the area between $z = -1.4$ and $z = 0.65$, subtract the smaller area from the larger one: $0.7422 - 0.0808 = 0.6614$

4. Convert the area to a percentage: Multiply the area by 100 to convert it into a percentage: $0.6614 \times 100 = 66.14\%$

Thus, the percent of the total area under the standard normal curve between $z = -1.4$ and $z = 0.65$ is approximately 66.1% (rounded to the nearest tenth).

Would you like more details on the normal distribution or how these values are derived?

Here are 5 related questions to consider:

1. How do you interpret the area under a normal distribution curve?
2. What is the relationship between standard deviation and z-scores?
3. How do you find the area between two negative z-scores?
4. What is the total area under the standard normal curve?
5. How can z-scores be used in real-world applications?

Tip: Always check the symmetry of the normal curve; for example, a positive z-score will have the same area as its corresponding negative z-score.