Math Problem Statement

Pada gambar-gambar di bawah ini gambarkan elemen luas pada partisi ke-i, lalu tentukan ΔL_i kemudian tuliskan integral yang menyatakan luas daerah tersebut.

Solution

The problem involves calculating the area between two curves for each of the four diagrams in the image. Here's a step-by-step approach to address each question:

  1. Identify the bounds of integration for each pair of curves: We need to determine where each pair of curves intersects to find the limits of integration.
  2. Set up the area element, ΔLi\Delta L_i: For each partition ii, ΔLi\Delta L_i represents the differential element of area. This is typically given by the difference between the top and bottom functions over the interval of integration.
  3. Write the integral expression: Integrate the difference between the upper and lower function over the interval to find the area.

Let's go through each case:

1. First Diagram (Top Left)

  • Functions: f(x)=2x2f(x) = 2 - x^2 and g(x)=xg(x) = x.
  • Intersection points: Solve 2x2=x2 - x^2 = x to determine the bounds.
  • Area element: ΔLi=(f(x)g(x))dx\Delta L_i = (f(x) - g(x)) \, dx.
  • Integral expression: Area=ab((2x2)x)dx\text{Area} = \int_a^b \left( (2 - x^2) - x \right) \, dx.

2. Second Diagram (Top Right)

  • Functions: f(x)=x+4f(x) = x + 4 and g(x)=x22g(x) = x^2 - 2.
  • Intersection points: Solve x+4=x22x + 4 = x^2 - 2 to find the limits.
  • Area element: ΔLi=(f(x)g(x))dx\Delta L_i = (f(x) - g(x)) \, dx.
  • Integral expression: Area=ab((x+4)(x22))dx\text{Area} = \int_a^b \left( (x + 4) - (x^2 - 2) \right) \, dx.

3. Third Diagram (Bottom Left)

  • Functions: y=x1y = x - 1 and x=3y2x = 3 - y^2.
  • Rewrite in terms of yy, if needed, or solve for the intersections in terms of xx and yy.
  • Integral expression will depend on the orientation; typically, in terms of dydy if integrating horizontally.

4. Fourth Diagram (Bottom Right)

  • Functions: y=xy = \sqrt{x} and y=6xy = 6 - x.
  • Intersection points: Solve x=6x\sqrt{x} = 6 - x to find the bounds.
  • Area element: ΔLi=(6xx)dx\Delta L_i = (6 - x - \sqrt{x}) \, dx.
  • Integral expression: Area=ab((6x)x)dx\text{Area} = \int_a^b \left( (6 - x) - \sqrt{x} \right) \, dx.

Would you like me to solve the integrals for each case or go through the steps for finding the bounds of integration in more detail?


Questions for Further Understanding:

  1. How do you find the intersection points of two functions?
  2. What are the steps to set up an area integral between curves?
  3. How do you determine if you should integrate with respect to xx or yy?
  4. Why is the upper function subtracted by the lower function in the area calculation?
  5. How can we verify the correctness of the integral setup for each region?

Tip: When solving for intersection points, setting the functions equal to each other and simplifying often provides the limits of integration quickly.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Calculus
Definite Integrals
Area Between Curves
Intersection Points

Formulas

Area between two curves: ∫[a,b] (f(x) - g(x)) dx
Intersection points by setting f(x) = g(x) and solving for x

Theorems

Fundamental Theorem of Calculus
Method for Area Between Two Curves

Suitable Grade Level

Undergraduate Calculus or Advanced High School Mathematics