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The question asks for the angular speed \( \omega_c \), which refers to the rate at which the amusement park ride is rotating. In physics, angular speed is a measure of how quickly an object rotates or revolves relative to another point, in this case, the axis \( AB \) of the ride. It's usually measured in radians per second (\(\text{rad/s}\)).

Here’s the approach to calculate \( \omega_c \) for this scenario:

1. **Forces involved**: The person \( P \) is kept against the wall by friction and the centrifugal force caused by the ride's rotation.
   - **Centrifugal force** \( F_{\text{centrifugal}} \): This is an outward force acting on the person due to the ride's spinning motion. The magnitude of the centrifugal force is:
     \[
     F_{\text{centrifugal}} = m \omega_c^2 d
     \]
     where:
     - \( m \) is the mass of the person,
     - \( d = 28 \, \text{ft} \) is the distance from the axis of rotation (converted to meters if necessary),
     - \( \omega_c \) is the angular speed.

2. **Frictional force** \( F_{\text{friction}} \): The friction force between the person and the wall prevents the person from sliding. The maximum frictional force is given by:
   \[
   F_{\text{friction}} = \mu_s N
   \]
   where:
   - \( \mu_s = 0.7 \) is the coefficient of static friction,
   - \( N \) is the normal force, which is the component of the centrifugal force perpendicular to the surface of the wall.

3. **Equilibrium**: For the person to not slide, the frictional force must equal the gravitational force pulling the person down. So:
   \[
   F_{\text{friction}} = mg
   \]
   And since \( N = F_{\text{centrifugal}} \cos(\theta) \), where \( \theta = 15^\circ \), we get:
   \[
   \mu_s F_{\text{centrifugal}} \cos(\theta) = mg
   \]
   Substituting \( F_{\text{centrifugal}} = m \omega_c^2 d \), we get:
   \[
   \mu_s (m \omega_c^2 d) \cos(\theta) = mg
   \]
   Simplifying, the mass \( m \) cancels out, and you can solve for \( \omega_c \):
   \[
   \omega_c = \sqrt{\frac{g}{\mu_s d \cos(\theta)}}
   \]
   where \( g = 9.81 \, \text{m/s}^2 \).

4. **Substitute values**: After converting \( d = 28 \, \text{ft} \) to meters (\( d \approx 8.5344 \, \text{m} \)), and using the values for \( \mu_s \), \( \theta \), and \( g \), you can calculate the angular speed \( \omega_c \).

Would you like the exact angular speed value with these substitutions? Feel free to ask for further clarification or details. 

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Here are five questions based on this concept:

1. How does the coefficient of friction affect the required angular speed to prevent sliding?
2. What would happen if the angle \( \theta \) increased?
3. How does the mass of the person impact the centrifugal force in this scenario?
4. What role does the normal force play in this system?
5. How would reducing the distance \( d \) from the axis affect the system?

**Tip:** Always ensure the units are consistent (e.g., feet to meters) when solving physics problems involving forces.

Learn how to calculate the angular speed (ω_c) required to keep a person from sliding in an amusement park ride with friction and centrifugal force. Using the concepts of friction, centripetal force, and equilibrium, this problem illustrates the step-by-step process for finding the angular speed. Suitable for Grades 11-12 physics students.

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