https://file.aiquickdraw.com/mathbot/file/172720354177368wt28qu.jpg

The image shows a right triangle with a right angle and two other angles provided: one is \( 32^\circ 30' \) and we are asked to calculate the angle \( x \).

In any triangle, the sum of all the angles is always \( 180^\circ \). Since this is a right triangle, we already know that one of the angles is \( 90^\circ \).

We can apply the angle sum property of triangles:

\[
90^\circ + 32^\circ 30' + x = 180^\circ
\]

Solving for \( x \):

\[
x = 180^\circ - 90^\circ - 32^\circ 30'
\]
\[
x = 90^\circ - 32^\circ 30' = 57^\circ 30'
\]

Therefore, the value of \( x \) is \( 57^\circ 30' \).

The correct answer is **A) 57º 30'**.

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Would you like further details or have any questions?

Here are 5 related questions for practice:
1. How do you calculate missing angles in any triangle?
2. What are the properties of right triangles?
3. If one of the angles of a triangle is \( 45^\circ \), what would be the measure of the third angle if it's a right triangle?
4. How can you convert degrees and minutes into decimal degrees?
5. How do the angles in a triangle change as the triangle shape changes?

**Tip:** In any right triangle, the two non-right angles always sum to \( 90^\circ \).

En el triángulo, calcular el ángulo x dado que uno de los ángulos es 32º 30' y hay un ángulo recto.

Solve for angle x in a right triangle with one angle measuring 32º 30'. This problem highlights the use of the triangle angle sum property and the right triangle theorem, suitable for students in Grades 6-8.

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