Math Problem Statement
The area of a rhombus is 143 sqm. If the longer diagonal is 26 m, find the angle opposite the shorter diagonal and the length of one side of the rhombus
Solution
To solve this problem, let's first recall the formula for the area of a rhombus. The area of a rhombus can be calculated using the lengths of its diagonals and :
Where:
- (the given area),
- (the longer diagonal),
- is the unknown shorter diagonal.
Step 1: Calculate the shorter diagonal
Substitute the known values into the formula and solve for :
Step 2: Calculate the side length of the rhombus
The diagonals of a rhombus bisect each other at right angles, so we can form two right triangles. The sides of these triangles are half of each diagonal and the side length of the rhombus is the hypotenuse of the triangle.
Half of the diagonals are:
Now, using the Pythagorean theorem:
So, the length of one side of the rhombus is approximately .
Step 3: Find the angle opposite the shorter diagonal
In the right triangle formed by half of each diagonal, we can use trigonometry to find the angle opposite the shorter diagonal. Specifically, we use the tangent function:
Let's calculate this:
Thus, the angle opposite the shorter diagonal is approximately .
Final answers:
- The length of one side of the rhombus is approximately .
- The angle opposite the shorter diagonal is approximately .
Would you like further details or have any questions?
Here are some related questions you might find useful:
- How do you calculate the area of a rhombus using its side and angle?
- What is the relationship between the diagonals of a rhombus?
- How do you find the perimeter of a rhombus given the diagonals?
- Can a rhombus have equal diagonals?
- What other properties do the angles in a rhombus have?
Tip: For rhombuses, diagonals always bisect each other at right angles, which is a useful fact for solving many problems!
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Math Problem Analysis
Mathematical Concepts
Geometry
Rhombus Properties
Pythagorean Theorem
Trigonometry
Formulas
Area of a rhombus: A = (1/2) * d1 * d2
Pythagorean theorem: s = sqrt((d1/2)^2 + (d2/2)^2)
Tangent function: tan(θ) = opposite/adjacent
Theorems
Pythagorean Theorem
Trigonometric Ratios
Suitable Grade Level
Grades 9-11
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