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This is a right-angled triangle \( \triangle LKM \) where angle \( \angle LKM = 90^\circ \). The given information includes:

- \( KL = 47 \)
- \( LM = 94 \)
- \( \angle KML = x^\circ \)

You are asked to find the value of \( x \).

We can use trigonometry to solve this, specifically the tangent function. Since we are given the opposite and adjacent sides, we can calculate the tangent of angle \( x \) as follows:

\[
\tan(x) = \frac{\text{opposite}}{\text{adjacent}} = \frac{KL}{LM} = \frac{47}{94}
\]

Let me calculate the value of \( x \).The value of \( x \) is approximately \( 26.57^\circ \).

Would you like any further details or explanations?

Here are some related questions you might find useful:

1. How can you use the sine or cosine function to verify the result?
2. What are the properties of a right-angled triangle relevant to solving such problems?
3. How do you find the length of the hypotenuse in this triangle?
4. What is the complementary angle of \( \angle KML \) in this triangle?
5. How can you apply the Pythagorean theorem in this triangle?

**Tip:** In trigonometry, if you know two sides of a right triangle, using tangent is often the simplest way to find an unknown angle!

Find the value of angle x in a right-angled triangle where KL = 47, LM = 94, and ∠LKM = 90°.

Learn how to find the value of an angle in a right-angled triangle using trigonometric ratios. Given sides KL = 47, LM = 94, and angle LKM = 90°, discover the step-by-step solution to calculate angle x using the tangent function. Suitable for students in Grades 8-10.

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