The ideal air to fuel ratio for an engine is 14.7​:1. If a vehicle burns 9 lb of​ fuel, how many pounds of air should it draw to achieve the ideal​ ratio?
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Part 1
The vehicle should draw

enter your response here lb of air to achieve the ideal ratio.
​(Round to the nearest whole number as​ needed.)

The ideal air-to-fuel ratio is 14.7:1, meaning for every 1 pound of fuel, 14.7 pounds of air are required.

If the vehicle burns 9 pounds of fuel, the amount of air needed can be calculated by multiplying the fuel by the air-to-fuel ratio:

\[
\text{Air required} = 9 \, \text{lb of fuel} \times 14.7 \, \frac{\text{lb of air}}{\text{lb of fuel}}
\]

Let's calculate this:

\[
\text{Air required} = 9 \times 14.7 = 132.3 \, \text{lb}
\]

Rounding to the nearest whole number:

\[
\text{Air required} = 132 \, \text{lb}
\]

So, the vehicle should draw **132 lb** of air to achieve the ideal ratio.

Would you like further details or have any questions? Here are some related questions:

1. How is the air-to-fuel ratio related to engine performance?
2. What happens if the air-to-fuel ratio is not ideal?
3. How can a vehicle's air-to-fuel ratio be adjusted?
4. What are the signs of a rich air-to-fuel mixture?
5. How does air density affect the air-to-fuel ratio?

**Tip**: Monitoring your vehicle's air-to-fuel ratio can improve fuel efficiency and reduce emissions.

The ideal air to fuel ratio for an engine is 14.7:1. If a vehicle burns 9 lb of fuel, how many pounds of air should it draw to achieve the ideal ratio?

Learn how to calculate the pounds of air needed to achieve the ideal 14.7:1 air-to-fuel ratio in an engine when burning 9 pounds of fuel. This problem involves ratios and basic multiplication, suitable for students in Grades 6-8.

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