The equation \( 36 \log 6 \) is asking for the multiplication of 36 by the logarithm of 6. The logarithm here is typically assumed to be the common logarithm (base 10) unless otherwise specified.

Let's calculate this:

\[
36 \log_{10} 6
\]

The logarithm of 6 in base 10 is approximately:

\[
\log_{10} 6 \approx 0.7782
\]

So:

\[
36 \times 0.7782 \approx 28.036
\]

Thus, \( 36 \log 6 \approx 28.036 \).

Would you like more details, or do you have any questions?

Here are some related questions:
1. What is the value of \( 20 \log 5 \)?
2. How do you calculate the logarithm of a number in a different base?
3. What is the difference between natural logarithm and common logarithm?
4. How would you solve \( x \log 6 = 12 \) for \( x \)?
5. What is the logarithm of 1 in any base?

**Tip:** When dealing with logarithms, it's important to know the base. If no base is specified, it is often assumed to be base 10 (common logarithm) or base \( e \) (natural logarithm).

Explore how to calculate 36 times the logarithm of 6 with detailed steps and formula application. Understand the logarithmic multiplication rule and its application in arithmetic operations. Suitable for high school students studying logarithms.

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