The problem shown in the image is asking to rewrite the exponential equation $36^x = 6$ in logarithmic form.

To convert an exponential equation to logarithmic form, the general rule is:

$a^x = b \quad \text{is equivalent to} \quad \log_a(b) = x$

For the given equation $36^x = 6$, using this rule:

$\log_{36}(6) = x$

So, the correct answer is the option: $\log_{36}(6) = x$

This corresponds to the fourth option on the list.

Would you like further details on logarithmic and exponential relationships or have any questions?

Here are 5 related questions to explore:

1. How do you convert logarithmic equations back into exponential form?
2. What is the logarithmic form of $10^x = 100$?
3. How do you solve for $x$ in logarithmic equations?
4. How does changing the base in an exponential equation affect the logarithmic form?
5. How can logarithms be used to solve real-world growth or decay problems?

Tip: To solve logarithmic equations, you can often use properties like the product, quotient, or power rules of logarithms.