Bryan decided to ride his bike along a new route home from school to avoid some construction. Before leaving school, he estimated how long the route would take. When Bryan arrived home, he saw the ride had taken him 16 minutes. His estimate had been 25% more than that. How long had Bryan estimated it would take to ride home from school?

Let \( t \) be the actual time Bryan took to ride home, which is given as 16 minutes. The problem states that Bryan's estimate was 25% more than the actual time.

To find the estimated time \( e \), we know that:

\[
e = t + 0.25t
\]

Substitute \( t = 16 \):

\[
e = 16 + 0.25 \times 16
\]
\[
e = 16 + 4 = 20
\]

Thus, Bryan had estimated it would take him **20 minutes** to ride home from school.

Would you like further details or have any questions?

Here are 5 related questions to think about:
1. If Bryan's ride home had taken 18 minutes, what would his estimated time have been?
2. How much longer did Bryan estimate his ride would take compared to the actual time?
3. What percentage of Bryan's estimated time was his actual ride time?
4. If Bryan wanted to reduce his riding time by 10%, how long would his new actual time be?
5. If Bryan had underestimated his ride time by 25%, what would his estimate have been?

**Tip:** When working with percentages, expressing the relationship as a decimal often simplifies calculations.

Learn how to solve a real-life percentage problem where Bryan's actual bike ride took 16 minutes, and his estimate was 25% more. This problem involves basic algebra and percentage calculations, ideal for students in Grades 6-8.

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