Math Problem Statement

A motor boat can maintain a constant speed of 19 miles per hour relative to the water. The boat makes a trip upstream to a certain point in 55 minutes the return trip takes 40 minutes. What is the speed of the current.

Solution

Let the speed of the current be cc miles per hour. The speed of the boat relative to the water is 19 miles per hour.

Step 1: Set up the relationships for the upstream and downstream trips.

  1. Upstream: When the boat is traveling upstream, it moves against the current, so its effective speed is 19c19 - c. The time taken for the upstream trip is 55 minutes, or 5560=1112\frac{55}{60} = \frac{11}{12} hours.

    Let the distance to the point be dd miles. So, d=(19c)×1112d = \left( 19 - c \right) \times \frac{11}{12}

  2. Downstream: When the boat is traveling downstream, it moves with the current, so its effective speed is 19+c19 + c. The time taken for the downstream trip is 40 minutes, or 4060=23\frac{40}{60} = \frac{2}{3} hours.

    The distance for the downstream trip is the same dd miles, so, d=(19+c)×23d = \left( 19 + c \right) \times \frac{2}{3}

Step 2: Set up an equation.

Since the distance dd is the same for both upstream and downstream trips, we can set the two expressions for dd equal to each other: (19c)×1112=(19+c)×23\left( 19 - c \right) \times \frac{11}{12} = \left( 19 + c \right) \times \frac{2}{3}

Step 3: Solve for cc.

To eliminate the fractions, multiply both sides by 12: 11×(19c)=8×(19+c)11 \times \left( 19 - c \right) = 8 \times \left( 19 + c \right)

Expanding both sides: 20911c=152+8c209 - 11c = 152 + 8c

Move the terms involving cc to one side and the constants to the other side: 209152=8c+11c209 - 152 = 8c + 11c 57=19c57 = 19c

Solve for cc: c=5719=3miles per hourc = \frac{57}{19} = 3 \, \text{miles per hour}

Final Answer:

The speed of the current is 33 miles per hour.

Would you like more details on any of the steps, or do you have any questions?

Here are 5 related questions to explore further:

  1. How would the problem change if the boat's speed relative to the water was 25 mph?
  2. What happens if the current speed increases by 2 mph?
  3. How long would the upstream trip take if the current speed was halved?
  4. What would the speed of the boat need to be to complete both trips in exactly 1 hour?
  5. If the boat travels in a river with no current, how does the total travel time change?

Tip: When dealing with problems involving relative speeds (like boats or planes in wind), always consider the combined effects of the moving medium (current or wind) on the object's speed.

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Math Problem Analysis

Mathematical Concepts

Algebra
Relative Speed
Linear Equations

Formulas

d = (19 - c) × (11/12)
d = (19 + c) × (2/3)
(19 - c) × (11/12) = (19 + c) × (2/3)

Theorems

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Suitable Grade Level

Grades 9-11