We can solve this problem using the binomial probability formula, since we are dealing with a fixed number of trials (7 adult smartphone users) and two possible outcomes for each trial: either the adult uses their smartphone in meetings or classes or they do not.

The binomial probability formula is:

$P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}$

Where:

• $n$ is the total number of trials (in this case, $n = 7$),
• $k$ is the number of successful trials (in this case, $k = 5, 6, \text{or} 7$),
• $p$ is the probability of success on a single trial (in this case, $p = 0.59$),
• $1-p$ is the probability of failure,
• $\binom{n}{k}$ is the binomial coefficient, which is calculated as $\frac{n!}{k!(n-k)!}$.

We need to find the probability of at least 5 adults using their smartphones in meetings or classes, which means we need to calculate:

$P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7)$

Let’s compute each probability step-by-step. I'll now calculate the exact values for you.The probability that at least 5 of the 7 selected adult smartphone users use their smartphones in meetings or classes is approximately 0.398 or 39.8%.

Would you like more details or have any questions?

Here are 5 related questions to deepen your understanding:

1. How would the probability change if the selection involved more adults (e.g., 10 adults)?
2. What if the probability of using smartphones in meetings increased to 70%? How would that affect the result?
3. Can you calculate the probability of exactly 6 adults using their smartphones in meetings?
4. How do we interpret the binomial coefficient in this context?
5. How would you modify this problem if there were 3 possible outcomes instead of 2?

Tip: When working with binomial probabilities, always ensure the trials are independent and the probability of success remains constant across all trials.