The problem describes a situation where we are interested in the number of students who will attend Tet festivities out of a group of 11 students. Since the students are selected randomly and each has the same probability of attending the festivities (20%), this follows a binomial distribution.

Key Information:

• Number of trials (n): 11 students surveyed
• Probability of success (p): 20% or 0.20 (probability that a student will attend Tet festivities)
• Random variable (X): The number of students who will attend the festivities.

The binomial distribution is given by:

$X \sim \text{Binomial}(n, p)$ Where:

• $n = 11$ (the number of students surveyed),
• $p = 0.20$ (the probability that a student attends the festivities).

Therefore, the distribution of $X$ is:

$X \sim \text{Binomial}(11, 0.20)$

This means that the random variable $X$ (the number of students who will attend Tet festivities) follows a binomial distribution with 11 trials (students) and a success probability of 0.20 (attendance rate).

Would you like me to calculate some probabilities or further details based on this distribution? Feel free to ask!

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Related Questions:

1. What is the probability that exactly 3 students will attend the Tet festivities?
2. How do you calculate the expected value and variance for a binomial distribution?
3. What is the probability that no students will attend the Tet festivities?
4. How would the distribution change if the probability of attending was 0.5 instead of 0.20?
5. What are the conditions for using a binomial distribution in real-life situations?

Tip: When using the binomial distribution, make sure that the trials are independent and that the probability of success remains constant across trials.