Math Problem Statement

Assume that a procedure yields a binomial distribution with a trial repeated n=5 times. Use some form of technology to find the probability distribution given the probability p=0.528
of success on a single trial.

(Report answers accurate to 4 decimal places.)

Solution

The binomial probability distribution for n=5n = 5 trials and a probability of success p=0.528p = 0.528 on a single trial is as follows:

  • P(X=0)=0.0234P(X = 0) = 0.0234
  • P(X=1)=0.1310P(X = 1) = 0.1310
  • P(X=2)=0.2932P(X = 2) = 0.2932
  • P(X=3)=0.3279P(X = 3) = 0.3279
  • P(X=4)=0.1834P(X = 4) = 0.1834
  • P(X=5)=0.0410P(X = 5) = 0.0410

These probabilities sum to 1, confirming the validity of the distribution.

Would you like more details or have any questions?

Here are some follow-up questions to explore further:

  1. What is the expected value of the binomial distribution in this case?
  2. How would you compute the variance and standard deviation of this distribution?
  3. What is the cumulative probability of getting at most 3 successes?
  4. How does changing pp to a lower or higher value affect the distribution shape?
  5. Can you derive the moment-generating function for a binomial distribution?

Tip: In binomial distributions, the probability of success pp and the number of trials nn significantly influence the skewness of the distribution.

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Math Problem Analysis

Mathematical Concepts

Probability
Binomial Distribution

Formulas

P(X = k) = (n choose k) * p^k * (1 - p)^(n-k)

Theorems

Binomial Theorem
Probability Distribution Theorem

Suitable Grade Level

Grades 11-12