Math Problem Statement
Suatu proses produksi menghasilkan sejumlah barang yang cacat sebanyak 10%. Bila 100 barang diambil secara random, maka hitung peluang: a) Tepat 10 yang cacat b) Antara 5 s/d 10 yang cacat c) Banyaknya cacat melebihi 14
Solution
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Math Problem Analysis
Mathematical Concepts
Probability
Binomial Distribution
Formulas
P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)
P(5 ≤ X ≤ 10) = P(X = 5) + P(X = 6) + ... + P(X = 10)
P(X > 14) = 1 - P(X ≤ 14)
Theorems
Binomial Theorem
Probability Theorem
Suitable Grade Level
Grade 11-12
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