Math Problem Statement

C(n+1, r), C(n, r) and C(n, r-1) are binomial coefficients and satisfies the condition C(n+1, r) = C(n, r) + C(n, r-1), which one of the following exist?

Solution

The problem you shared involves binomial coefficients and asks to identify the correct relationship that holds between different binomial terms.

Given:

  • C(n+1,r)=C(n,r)+C(n,r1)C(n+1, r) = C(n, r) + C(n, r-1) is the key identity based on Pascal's identity for binomial coefficients.

We need to identify which of the provided options follows this identity. Let's analyze them:

Option A:

C(n1,r)+C(n1,r1)=C(n,r1)C(n-1, r) + C(n-1, r-1) = C(n, r-1) This is Pascal's identity but shifted for the lower terms n1n-1. This looks plausible, but let's check other options.

Option B:

C(n1,r)+C(n1,r+1)=C(n,r)C(n-1, r) + C(n-1, r+1) = C(n, r) This does not align with Pascal’s identity as the second term involves r+1r+1.

Option C:

C(n1,r1)+C(n1,r2)=C(n,r1)C(n-1, r-1) + C(n-1, r-2) = C(n, r-1) This does not fit either because Pascal’s identity involves only rr and r1r-1, but here we have r1r-1 and r2r-2.

Option D:

C(n1,r)+C(n1,r2)=C(n,r1)C(n-1, r) + C(n-1, r-2) = C(n, r-1) This again doesn’t follow Pascal’s identity.

Conclusion:

Option A is the correct one. It follows Pascal's identity: C(n,r)=C(n1,r)+C(n1,r1)C(n, r) = C(n-1, r) + C(n-1, r-1)

Would you like more details on how Pascal's identity works? Let me know if you have any other questions!

Related questions:

  1. What is Pascal’s triangle, and how does it relate to binomial coefficients?
  2. How are binomial coefficients used in the expansion of (x+y)n(x + y)^n?
  3. Can Pascal’s identity be derived using combinatorial arguments?
  4. How do binomial coefficients relate to combinations and counting problems?
  5. How does Pascal’s identity apply in recursive algorithms?

Tip:

When dealing with binomial coefficients, remembering Pascal's triangle and identity will help you quickly verify relationships!

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Binomial Coefficients
Pascal's Identity

Formulas

C(n+1, r) = C(n, r) + C(n, r-1) (Pascal's Identity)

Theorems

Pascal's Identity

Suitable Grade Level

Grades 10-12