The image shows a binary subtraction problem:

$1101_{\text{two}} - \Box_{\text{two}} = 1010_{\text{two}}$

To solve for the missing value in the box, follow these steps:

1. Convert the given binary numbers to decimal:

   • $1101_{\text{two}}$ in decimal is $1 \times 2^3 + 1 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 8 + 4 + 0 + 1 = 13_{\text{ten}}$
   • $1010_{\text{two}}$ in decimal is $1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 0 \times 2^0 = 8 + 0 + 2 + 0 = 10_{\text{ten}}$

2. Subtract the decimal equivalent of $1010_{\text{two}}$ from $1101_{\text{two}}$: $13_{\text{ten}} - 10_{\text{ten}} = 3_{\text{ten}}$

3. Convert the result $3_{\text{ten}}$ back to binary: $3_{\text{ten}} = 11_{\text{two}}$

So, the missing value in the box is $11_{\text{two}}$.

Thus, the complete equation is:

$1101_{\text{two}} - 11_{\text{two}} = 1010_{\text{two}}$

Would you like further clarification on any part of the solution?

Here are 5 related questions you might find useful:

1. How do you convert binary numbers to decimal?
2. How can you subtract two binary numbers directly?
3. What are the rules for binary addition and subtraction?
4. How does binary arithmetic differ from decimal arithmetic?
5. Can binary operations be extended to hexadecimal numbers?

Tip: When subtracting in binary, always remember to borrow from the left just like in decimal subtraction, but borrowing occurs in powers of 2 instead of 10.