Math Problem Statement

In the set of integers \( \mathbb{Z} \), an operation \( a \circ b = -2ab \) is given. Is the operation commutative? Is the operation associative? Does the operation have a neutral element?

Solution

The image presents a binary operation defined on the set of integers Z\mathbb{Z}, given by:

ab=2aba \circ b = -2ab

You are being asked the following three questions about this operation:

  1. Is the operation commutative?
  2. Is the operation associative?
  3. Does the operation have a neutral (identity) element?

Let's analyze each of these properties.

1. Commutativity

An operation is commutative if ab=baa \circ b = b \circ a for all aa and bb in Z\mathbb{Z}.

For the operation ab=2aba \circ b = -2ab, let's check commutativity:

ab=2aba \circ b = -2ab ba=2bab \circ a = -2ba

Since multiplication of integers is commutative (ab=baab = ba), we have 2ab=2ba-2ab = -2ba. Therefore, the operation is commutative.

2. Associativity

An operation is associative if (ab)c=a(bc)(a \circ b) \circ c = a \circ (b \circ c) for all aa, bb, and cc in Z\mathbb{Z}.

Let's check this for ab=2aba \circ b = -2ab.

First, calculate (ab)c(a \circ b) \circ c: ab=2ab,(ab)c=(2ab)c=2(2ab)c=4abca \circ b = -2ab, \quad (a \circ b) \circ c = (-2ab) \circ c = -2(-2ab)c = 4abc

Now, calculate a(bc)a \circ (b \circ c): bc=2bc,a(bc)=a(2bc)=2a(2bc)=4abcb \circ c = -2bc, \quad a \circ (b \circ c) = a \circ (-2bc) = -2a(-2bc) = 4abc

Since (ab)c=a(bc)=4abc(a \circ b) \circ c = a \circ (b \circ c) = 4abc, the operation is associative.

3. Neutral (Identity) Element

An operation has a neutral element ee if ae=aa \circ e = a for all aZa \in \mathbb{Z}.

For the operation ae=2ae=aa \circ e = -2ae = a, solving for ee: 2ae=a    e=12-2ae = a \implies e = -\frac{1}{2}

However, e=12e = -\frac{1}{2} is not an integer, and since the operation is defined on Z\mathbb{Z}, the set of integers, there is no neutral element in Z\mathbb{Z}. Therefore, the operation does not have a neutral element.

Summary:

  1. The operation is commutative.
  2. The operation is associative.
  3. The operation does not have a neutral element.

Would you like further details or clarifications? Here are five follow-up questions related to this:

  1. What happens if we define this operation on the set of rational numbers Q\mathbb{Q}?
  2. How does this operation compare to the standard multiplication operation in Z\mathbb{Z}?
  3. What are some examples of non-associative operations?
  4. Could an identity element exist if we extend the set to non-integers?
  5. How would we verify if an operation is distributive over addition?

Tip: When verifying commutativity or associativity, always expand both sides of the equation independently before comparing them.

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Math Problem Analysis

Mathematical Concepts

Binary Operation
Commutativity
Associativity
Neutral Element
Algebra

Formulas

a \circ b = -2ab
Commutativity: a \circ b = b \circ a
Associativity: (a \circ b) \circ c = a \circ (b \circ c)

Theorems

Commutativity and Associativity Properties
Existence of Identity Element

Suitable Grade Level

Grades 9-12