Math Problem Statement
Let S be a set. Prove that the law of composition defined by ab=a for all a and b in S is associative. For which sets does this law ha identity?
Solution
We are given a set with a binary operation defined by for all , and we are asked to:
- Prove that the operation is associative.
- Determine if this operation has an identity element and for which sets this law has one.
1. Prove that the operation is associative
The operation is defined by for all . To prove that the operation is associative, we must show that for all , we have:
Left-hand side:
(because by the definition of the operation).
Right-hand side:
(because by the definition of the operation).
But we know that , so:
Thus, we have:
This shows that the operation is associative for all .
2. Identity element of the operation
An identity element must satisfy:
From the definition of the operation is always true, regardless of , because for any .
However, by the definition of the operation, but for to be an identity element, we require . Thus, for all , which implies that must contain only one element. In other words, for some element .
Conclusion:
- The operation defined by is associative for any set .
- The operation has an identity element only if is a singleton set, i.e., .
Would you like further details on any part of this explanation?
Here are some related questions:
- How do we determine if an operation is commutative?
- Can an operation have multiple identity elements?
- What are some examples of non-associative operations?
- How would the proof change if instead of ?
- Can we extend this operation to infinite sets?
Tip: In associative operations, the grouping of elements doesn’t affect the result, but commutative operations require order to not matter either.
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Math Problem Analysis
Mathematical Concepts
Abstract Algebra
Binary Operations
Associativity
Identity Element
Formulas
(a * b) * c = a * (b * c)
a * e = a
e * a = a
Theorems
Associative Property
Identity Element Condition
Suitable Grade Level
College-Level Abstract Algebra
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