Math Problem Statement

x^{2}+8x+7 What happens to the y-values as x increases and as x decreases

Solution

The given quadratic expression is:

y=x2+8x+7y = x^2 + 8x + 7

Behavior of the function as xx increases and decreases:

  1. As xx increases (positive values of xx):

    • The term x2x^2 becomes increasingly large.
    • The linear term 8x8x also increases but at a slower rate compared to x2x^2.
    • As a result, the yy-values increase rapidly as xx increases.
  2. As xx decreases (negative values of xx):

    • The quadratic term x2x^2 still grows, but it grows positively since squaring any number gives a positive result.
    • The term 8x8x becomes more negative (since xx is negative), but the x2x^2 term dominates for large negative values.
    • Therefore, the yy-values still increase as xx decreases significantly in magnitude.

Conclusion:

  • As xx increases or decreases significantly, yy-values grow larger due to the dominance of the x2x^2 term. The graph of this quadratic function is a parabola opening upwards, meaning it has a minimum point (vertex) and then rises as you move in either direction away from the vertex.

Do you want further details or explanations about this?

Here are 5 related questions:

  1. What is the vertex of the quadratic function?
  2. How do you find the axis of symmetry for a parabola?
  3. How does the sign of the coefficient of x2x^2 affect the direction of the parabola?
  4. Can you find the roots of the quadratic equation?
  5. What is the minimum value of this quadratic function?

Tip: The turning point of a parabola (vertex) gives useful information about where the function reaches its minimum or maximum value.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Parabolas
Behavior of Quadratic Functions

Formulas

Quadratic function: y = ax^2 + bx + c

Theorems

Properties of Parabolas
Vertex Form of Quadratic Functions

Suitable Grade Level

Grades 8-10