Math Problem Statement

  1. Due to outbreak of a new virus in a city 30% of the total population of the city are infected by the new virus. The probability that a certain kit correctly diagnoses the infection for a patent when the patient is indeed infected by the new virus is 0.80. Whereas the kit gives positive result for a given patient when the patient is actually not infected by the virus with probability 0.15. Suppose that for a particular patient the test result comes out to be positive. What is the probability that the patient is not infected by the new virus?

Solution

To solve this problem, we can use Bayes' Theorem, which provides a way to update the probability of an event based on new evidence.

Given:

  • P(I)=0.30P(I) = 0.30 is the probability that a person is infected by the virus.
  • P(NI)=0.70P(NI) = 0.70 is the probability that a person is not infected by the virus.
  • P(Positive TestI)=0.80P(\text{Positive Test} | I) = 0.80 is the probability that the test is positive given the person is infected.
  • P(Positive TestNI)=0.15P(\text{Positive Test} | NI) = 0.15 is the probability that the test is positive given the person is not infected.

We are asked to find the probability that a patient is not infected given a positive test result, i.e., we want to compute P(NIPositive Test)P(NI | \text{Positive Test}).

Bayes' Theorem:

Bayes' Theorem states:

P(NIPositive Test)=P(Positive TestNI)P(NI)P(Positive Test)P(NI | \text{Positive Test}) = \frac{P(\text{Positive Test} | NI) \cdot P(NI)}{P(\text{Positive Test})}

Where P(Positive Test)P(\text{Positive Test}) is the total probability of a positive test result, which can be found using the law of total probability:

P(Positive Test)=P(Positive TestI)P(I)+P(Positive TestNI)P(NI)P(\text{Positive Test}) = P(\text{Positive Test} | I) \cdot P(I) + P(\text{Positive Test} | NI) \cdot P(NI)

Step-by-step Calculation:

  1. Calculate P(Positive Test)P(\text{Positive Test}): P(Positive Test)=(0.800.30)+(0.150.70)P(\text{Positive Test}) = (0.80 \cdot 0.30) + (0.15 \cdot 0.70) P(Positive Test)=0.24+0.105=0.345P(\text{Positive Test}) = 0.24 + 0.105 = 0.345

  2. Calculate P(NIPositive Test)P(NI | \text{Positive Test}): P(NIPositive Test)=(0.150.70)0.345P(NI | \text{Positive Test}) = \frac{(0.15 \cdot 0.70)}{0.345} P(NIPositive Test)=0.1050.3450.3043P(NI | \text{Positive Test}) = \frac{0.105}{0.345} \approx 0.3043

Thus, the probability that the patient is not infected given that the test result is positive is approximately 0.3043 or 30.43%.


Would you like a further breakdown or have additional questions?

Here are some related questions to expand on the topic:

  1. How can Bayes' Theorem be applied to other types of diagnostic tests?
  2. What happens if the probability of a false positive is reduced (i.e., P(Positive TestNI)P(\text{Positive Test} | NI))?
  3. How would the result change if the infection rate of the population increased to 50%?
  4. What other factors might affect the reliability of diagnostic tests in real-world scenarios?
  5. How can we assess the accuracy of a diagnostic test more comprehensively?

Tip: When using Bayes' Theorem in diagnostic problems, always ensure you correctly account for both the true positive and false positive rates.

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Math Problem Analysis

Mathematical Concepts

Probability
Bayes' Theorem
Conditional Probability

Formulas

P(NI | Positive Test) = (P(Positive Test | NI) * P(NI)) / P(Positive Test)
P(Positive Test) = P(Positive Test | I) * P(I) + P(Positive Test | NI) * P(NI)

Theorems

Bayes' Theorem

Suitable Grade Level

Grades 10-12