Math Problem Statement

Solve this

A survey found that machine A produces 30% of the items and machine B produces 70% of the items. Furthermore, 4% and 2% of the items produced by machines A and B respectively were defective. If a randomly selected item is defective, what is the probability that it was produced by machine B?

Solution

This problem involves conditional probability, so let's break it down systematically.

We have the following information:

  • Machine A produces 30% of the items, and machine B produces 70%.
  • Of the items produced by machine A, 4% are defective.
  • Of the items produced by machine B, 2% are defective.

We need to find the probability that a randomly selected defective item was produced by machine B.

Step 1: Define the events

Let:

  • AA be the event that the item was produced by machine A.
  • BB be the event that the item was produced by machine B.
  • DD be the event that the item is defective.

Step 2: Known probabilities

From the problem:

  • P(A)=0.30P(A) = 0.30, P(B)=0.70P(B) = 0.70
  • P(DA)=0.04P(D|A) = 0.04 (probability of being defective given that it was produced by machine A)
  • P(DB)=0.02P(D|B) = 0.02 (probability of being defective given that it was produced by machine B)

We are asked to find the probability that a randomly selected defective item was produced by machine B, i.e., P(BD)P(B|D).

Step 3: Apply Bayes' Theorem

Bayes' Theorem states that: P(BD)=P(DB)P(B)P(D)P(B|D) = \frac{P(D|B)P(B)}{P(D)} Where P(D)P(D) is the total probability that an item is defective. We can compute P(D)P(D) using the law of total probability: P(D)=P(DA)P(A)+P(DB)P(B)P(D) = P(D|A)P(A) + P(D|B)P(B) Substitute the known values: P(D)=(0.04)(0.30)+(0.02)(0.70)P(D) = (0.04)(0.30) + (0.02)(0.70) Now calculate P(D)P(D).

Step 4: Compute the probability

After computing P(D)P(D), we can use Bayes' Theorem to find P(BD)P(B|D).

Let me compute this step for you. Given values P_A = 0.30 # Probability that item was produced by A P_B = 0.70 # Probability that item was produced by B P_D_given_A = 0.04 # Probability that item is defective given it was produced by A P_D_given_B = 0.02 # Probability that item is defective given it was produced by B

Total probability of defect (P(D))

P_D = (P_D_given_A * P_A) + (P_D_given_B * P_B)

Calculate P(B|D) using Bayes' Theorem

P_B_given_D = (P_D_given_B * P_B) / P_D P_B_given_DThe probability that a randomly selected defective item was produced by machine B is approximately 0.5380.538 or 53.85%.

Would you like a more detailed breakdown of any part of this solution? Let me know if you need further clarifications.

Here are some related questions for you to explore:

  1. How does the probability change if the defect rate of machine A increases?
  2. What happens to the probability if the production rates of machine A and B are swapped?
  3. How does Bayes' Theorem apply in situations with more than two machines or categories?
  4. What is the importance of the prior probabilities P(A)P(A) and P(B)P(B) in Bayesian analysis?
  5. How can we visualize this probability using a Venn diagram?

Tip: When working with Bayes' Theorem, always ensure that the sum of all prior probabilities equals 1 (i.e., P(A)+P(B)=1P(A) + P(B) = 1) for a complete and consistent solution.

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Math Problem Analysis

Mathematical Concepts

Conditional Probability
Bayes' Theorem
Total Probability

Formulas

P(B|D) = (P(D|B) * P(B)) / P(D)
P(D) = P(D|A) * P(A) + P(D|B) * P(B)

Theorems

Bayes' Theorem

Suitable Grade Level

Grades 11-12