Math Problem Statement

Differentiate the function using basic differentiation formulas. (a) f(x) = π 2 (b) f(x) = 3 4 x 8 (c) f(t) = 1.4t 5 − 2.5t 2 + 6.7 (d) y = sin(t) + π cos(t) (e) B(y) = cy−6 (f) y = x 5/3 − x 2/3 (g) y = √ x(x − 1) (h) S(R) = 4πR2 (i) g(u) = √ 2u + √ 3u (j) y = √ x+x x2 (k) f(θ) = sin(θ) 2 + c θ (l) f(t) = √3 t 2 + 2√ t 3

Solution

Let's differentiate each function using basic differentiation rules.

(a) f(x)=πf(x) = \pi

Since π\pi is a constant, its derivative is 0. f(x)=0f'(x) = 0


(b) f(x)=34x8f(x) = \frac{3}{4} x^8

Using the power rule, ddx(xn)=nxn1\frac{d}{dx}(x^n) = nx^{n-1}: f(x)=348x81=6x7f'(x) = \frac{3}{4} \cdot 8x^{8-1} = 6x^7


(c) f(t)=1.4t52.5t2+6.7f(t) = 1.4t^5 - 2.5t^2 + 6.7

Differentiate each term separately: f(t)=1.45t512.52t21+0=7t45tf'(t) = 1.4 \cdot 5t^{5-1} - 2.5 \cdot 2t^{2-1} + 0 = 7t^4 - 5t


(d) y=sin(t)+πcos(t)y = \sin(t) + \pi \cos(t)

Differentiate each term: y=cos(t)πsin(t)y' = \cos(t) - \pi \sin(t)


(e) B(y)=cy6B(y) = cy^{-6}

Using the power rule and constant multiple rule, where cc is a constant: B(y)=c(6)y7=6cy7B'(y) = c \cdot (-6)y^{-7} = -6cy^{-7}


(f) y=x5/3x2/3y = x^{5/3} - x^{2/3}

Differentiate each term using the power rule: y=53x53123x231=53x2/323x1/3y' = \frac{5}{3}x^{\frac{5}{3} - 1} - \frac{2}{3}x^{\frac{2}{3} - 1} = \frac{5}{3}x^{2/3} - \frac{2}{3}x^{-1/3}


(g) y=x(x1)y = \sqrt{x}(x - 1)

Rewrite the function as y=x1/2(x1)y = x^{1/2}(x - 1) and apply the product rule, (uv)=uv+uv(uv)' = u'v + uv': y=12x12(x1)+x121y' = \frac{1}{2}x^{-\frac{1}{2}}(x - 1) + x^{\frac{1}{2}} \cdot 1 Simplify: y=x12x+xy' = \frac{x - 1}{2\sqrt{x}} + \sqrt{x}


(h) S(R)=4πR2S(R) = 4\pi R^2

Differentiate with respect to RR: S(R)=4π2R=8πRS'(R) = 4\pi \cdot 2R = 8\pi R


(i) g(u)=2u+3ug(u) = \sqrt{2u} + \sqrt{3u}

Rewrite as g(u)=(2u)1/2+(3u)1/2g(u) = (2u)^{1/2} + (3u)^{1/2}, then differentiate: g(u)=12(2u)1/22+12(3u)1/23g'(u) = \frac{1}{2}(2u)^{-1/2} \cdot 2 + \frac{1}{2}(3u)^{-1/2} \cdot 3 =12u+323u= \frac{1}{\sqrt{2u}} + \frac{3}{2\sqrt{3u}}


(j) y=x+xx2y = \frac{\sqrt{x} + x}{x^2}

Rewrite as y=x1/2x2+xx2=x3/2+x1y = \frac{x^{1/2}}{x^2} + \frac{x}{x^2} = x^{-3/2} + x^{-1} and differentiate: y=32x5/2x2=32x5/21x2y' = -\frac{3}{2}x^{-5/2} - x^{-2} = -\frac{3}{2x^{5/2}} - \frac{1}{x^2}


(k) f(θ)=sin2(θ)+cθf(\theta) = \sin^2(\theta) + \frac{c}{\theta}

Differentiate sin2(θ)\sin^2(\theta) using the chain rule and apply the power rule to cθ\frac{c}{\theta}: f(θ)=2sin(θ)cos(θ)cθ2=sin(2θ)cθ2f'(\theta) = 2\sin(\theta)\cos(\theta) - \frac{c}{\theta^2} = \sin(2\theta) - \frac{c}{\theta^2}


(l) f(t)=3t2+2t3f(t) = \sqrt{3}t^2 + 2\sqrt{t^3}

Rewrite 2t32\sqrt{t^3} as 2t3/22t^{3/2}: f(t)=32t+232t1/2=23t+3t1/2f'(t) = \sqrt{3} \cdot 2t + 2 \cdot \frac{3}{2}t^{1/2} = 2\sqrt{3}t + 3t^{1/2}


Would you like further explanations on any of these steps?

Related Questions

  1. How would you apply the product rule for more complex products?
  2. What are the differences between using the chain rule and the power rule?
  3. How do you approach differentiating trigonometric functions?
  4. Can you explain implicit differentiation with an example?
  5. How would you find the second derivative of one of these functions?

Tip

When differentiating, it’s often helpful to rewrite the function in a simpler form before applying differentiation rules.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Basic differentiation rules
Trigonometric differentiation
Product rule
Power rule
Chain rule

Formulas

d/dx(c) = 0 for constants
d/dx(x^n) = n*x^(n-1) for power functions
d/dx(sin(x)) = cos(x)
d/dx(cos(x)) = -sin(x)
Product rule: (uv)' = u'v + uv'
Chain rule: (f(g(x)))' = f'(g(x)) * g'(x)

Theorems

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Suitable Grade Level

Grades 11-12 or early university calculus