https://file.aiquickdraw.com/mathbot/file/1727769143895jlmz537o.jpg

Let's go through the process of differentiating each function one by one.

### 1. \( y = x^2 - 2x^4 - 3x^5 \)
Differentiate term by term using the power rule: \(\frac{d}{dx} x^n = nx^{n-1}\).

\[
\frac{dy}{dx} = 2x - 8x^3 - 15x^4
\]

### 2. \( y = 5x^{-2} + x^{-3} \)
Again, apply the power rule.

\[
\frac{dy}{dx} = -10x^{-3} - 3x^{-4}
\]

### 3. \( y = \frac{1}{v^2} - \frac{2}{v^4} \)
Rewrite the terms as powers of \( v \) and then differentiate.

\[
y = v^{-2} - 2v^{-4}
\]
\[
\frac{dy}{dv} = -2v^{-3} + 8v^{-5}
\]

### 4. \( y = \frac{2}{3} - \frac{y^2}{5} + \frac{4y^3}{3} \)
Differentiate term by term. The constant \( \frac{2}{3} \) will disappear since the derivative of a constant is 0.

\[
\frac{dy}{dy} = 0 - \frac{2y}{5} + 4y^2
\]

### 5. \( y = 6 - x^{-4/3} \)
Differentiate both terms. The constant 6 disappears, and apply the power rule to the second term.

\[
\frac{dy}{dx} = \frac{4}{3}x^{-7/3}
\]

### 6. \( x = \sqrt{t} - \frac{1}{\sqrt{t}} \)
Rewrite in terms of powers of \( t \), i.e., \( t^{1/2} \) and \( t^{-1/2} \), then differentiate.

\[
\frac{dx}{dt} = \frac{1}{2}t^{-1/2} + \frac{1}{2}t^{-3/2}
\]

### 7. \( y = (v^2 + 3)(v^2 - v + 1) \)
Use the product rule: \( \frac{d}{dv}(uv) = u'v + uv' \).

\[
\frac{dy}{dv} = \left(2v\right)(v^2 - v + 1) + (v^2 + 3)(2v - 1)
\]
Simplify:
\[
\frac{dy}{dv} = 2v(v^2 - v + 1) + (v^2 + 3)(2v - 1)
\]

### 8. \( x = \frac{3}{t^2 - 1} \)
This is a quotient. Use the quotient rule: \( \frac{d}{dt}\left(\frac{u}{v}\right) = \frac{u'v - uv'}{v^2} \).

\[
\frac{dx}{dt} = \frac{0(t^2 - 1) - 3(2t)}{(t^2 - 1)^2} = \frac{-6t}{(t^2 - 1)^2}
\]

### 9. \( y = \frac{x}{x^2 - 1} \)
Use the quotient rule again.

\[
\frac{dy}{dx} = \frac{(1)(x^2 - 1) - x(2x)}{(x^2 - 1)^2} = \frac{x^2 - 1 - 2x^2}{(x^2 - 1)^2} = \frac{-x^2 - 1}{(x^2 - 1)^2}
\]

### 10. \( f(x) = \frac{x(x+1)}{x^2 - 1} \)
Use the product rule and the quotient rule together.

First, differentiate \( x(x+1) = x^2 + x \), which gives \( 2x + 1 \).

Now use the quotient rule:
\[
f'(x) = \frac{(2x+1)(x^2 - 1) - (x^2 + x)(2x)}{(x^2 - 1)^2}
\]
Simplify this expression.

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Do you need any of the solutions simplified further or explained in more detail? Feel free to ask for clarification!

### Related Questions:
1. What is the power rule for differentiation and how is it applied?
2. How do you handle differentiation of products like in problem 7?
3. What is the quotient rule and how does it work for problems 8 and 9?
4. Why do constants vanish when differentiating?
5. What are common mistakes to avoid when using the product and quotient rules?

### Tip:
Always simplify the function as much as possible before differentiating to avoid unnecessary complications!

Solve the following problems. Differentiate the functions from the image: (1) y = x^2 - 2x^4 - 3x^5, (2) y = 5x^{-2} + x^{-3}, (3) y = 1/v^2 - 2/v^4, (4) y = 2/3 - y^2/5 + 4y^3/3, (5) y = 6 - x^{-4/3}, (6) x = sqrt(t) - 1/sqrt(t), (7) y = (v^2 + 3)(v^2 - v + 1), (8) x = 3/(t^2 - 1), (9) y = x/(x^2 - 1), (10) f(x) = x(x+1)/(x^2 - 1).

Learn how to differentiate a variety of functions using the power, quotient, and product rules. This detailed guide walks through the differentiation process for 10 different functions, including polynomial, rational, and radical expressions. Suitable for students in Grades 11-12 or early university calculus.

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