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The problem shows a triangular banner, where the dimensions given in the drawing are 6 inches in height and 8 inches in width. The scale of the drawing is 1 inch = \( \frac{1}{2} \) feet on the actual banner. 

### Step-by-step solution:

1. **Convert the dimensions to actual size**:
   - Height: \( 6 \text{ in} \times \frac{1}{2} = 3 \text{ feet} \)
   - Width: \( 8 \text{ in} \times \frac{1}{2} = 4 \text{ feet} \)

2. **Calculate the area of the triangular banner**:
   The formula for the area of a triangle is:
   \[
   \text{Area} = \frac{1}{2} \times \text{Base} \times \text{Height}
   \]
   Here, the base is 4 feet and the height is 3 feet.
   \[
   \text{Area} = \frac{1}{2} \times 4 \times 3 = 6 \text{ square feet}
   \]

So, the area of the actual banner is **6 square feet**.

Would you like more details or have any questions? 

Here are 5 related questions to explore:
1. How do you apply different scale factors in geometry problems?
2. What is the formula for the area of other geometric shapes?
3. How does changing the scale affect the area of a shape?
4. What are some practical applications of using scale drawings in real life?
5. How would the problem change if the shape was a rectangle instead of a triangle?

**Tip:** When converting measurements in a scale drawing, ensure that both dimensions (height and width) are multiplied by the same scale factor to maintain accuracy.

What is the area of the actual banner, given that the scale drawing shows dimensions of 6 inches by 8 inches and 1 inch on the drawing represents 1/2 foot on the actual banner?

Learn how to find the area of an actual triangular banner using a scale drawing where 1 inch represents 1/2 foot. This problem covers key geometry concepts, including using a scale factor and calculating the area of a triangle. Suitable for Grades 6-8 students.

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