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This problem involves balancing a lever using the principle of moments (also known as torque). The torque is calculated as the product of the weight and its distance from the fulcrum. For the lever to be balanced, the torques on both sides must be equal.

### Given:
- On the left side: 
  - Weight = 5 lb
  - Distance from the fulcrum = 2 ft
- On the right side:
  - Weight = \( W \) lb (the unknown weight)
  - Distance from the fulcrum = 5 ft

### Balancing equation:
The torque on the left side must equal the torque on the right side:
\[
\text{Torque}_{\text{left}} = \text{Torque}_{\text{right}}
\]
\[
5 \, \text{lb} \times 2 \, \text{ft} = W \, \text{lb} \times 5 \, \text{ft}
\]
Solving for \( W \):
\[
10 = 5W
\]
\[
W = \frac{10}{5} = 2 \, \text{lb}
\]

### Answer:
The unknown weight is **2 lb**.

Would you like more details or have any further questions?

Here are 5 related questions for practice:
1. What happens to the weight if the distance on the right side is halved?
2. If the left-side weight were doubled, what would be the new weight on the right side?
3. How would the system balance if both weights were moved closer to the fulcrum?
4. If the weight on the left was 10 lb, what would the weight on the right be?
5. How does the principle of moments apply in real-world scenarios like seesaws?

**Tip**: Always remember that the farther an object is from the fulcrum, the greater the force (or weight) required on the other side to balance it.

The scale is balanced. What weight is the weight with the question mark?

Learn how to balance a lever using the principle of moments and solve for the unknown weight. This physics problem involves calculating torque by multiplying force (weight) by distance from the fulcrum. The problem is ideal for students in Grades 6-8.

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