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Give me the formula for this question not answer

The question you've provided relates to the principle of levers, specifically the **law of the lever**, which states that for a lever to be in equilibrium, the moments about the fulcrum must be equal.

The moment (or torque) is calculated as:

\[
\text{Moment} = \text{Force} \times \text{Distance from the Fulcrum}
\]

In this case:

- The force on the left side is \( 120 \, \text{lb} \), and its distance from the fulcrum is \( 4 \, \text{ft} \).
- The force on the right side is \( 100 \, \text{lb} \), and its distance from the fulcrum is \( x \, \text{ft} \), which we need to find.

To achieve equilibrium (or "just tip the lever"), the moments on both sides of the fulcrum must be equal:

\[
120 \, \text{lb} \times 4 \, \text{ft} = 100 \, \text{lb} \times x
\]

This gives the formula:

\[
x = \frac{120 \times 4}{100}
\]

This formula will help you solve for the distance \( x \) that the \( 100 \, \text{lb} \) weight needs to be placed from the fulcrum to balance the lever.

Would you like to proceed with solving this or explore more details?

### Related Questions:
1. How does the mass on each side affect the balance of a lever?
2. What happens if the weight of the object on the left is increased?
3. Can you explain the concept of torque in more detail?
4. How is this principle of levers applied in everyday machines?
5. What is the difference between a first-class and second-class lever?

**Tip:** Always remember to check units when calculating moments to ensure accuracy!

How far from the fulcrum does the 100 lb weight need to be to just tip the lever?

Explore the physics behind lever balance by calculating the distance needed for a 100 lb weight to just tip the lever. This problem demonstrates the law of the lever and the calculation of torque and equilibrium.

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