Math Problem Statement

Complete the table below. (Measure all angles between 0° and 360°, counterclockwise from the +x-axis.) Data Table 1 Force Mass (kg) Force (N) Angle (degrees) |x-component (N) y-component (N) F₁ 0.150 1.47 60 0.735 1.273 ✓ F₂ 0.150 1.47 300 0.735 -1.273 R = F₁+F₂ Resultant = 1.47 0 ✓ Equilibrant = -1.47 ✔ What is the calculated value of F3 (equilibrant) needed to balance the two forces F₁ and F₂? magnitude F3,calc = 1.47 N direction 03,calc = 180 What is the experimental value of F3 (equilibrant) needed to balance the two forces F₁ and F2? magnitude F3,exp = direction 03,exp = What is the percent difference between the calculated and experimental values of the magnitude of F3? (Percent differences should not be rounded to one significant HINT figure.) percent difference = % What is the percent difference between the calculated and experimental values of 03? (Percent differences should not be rounded to one significant figure.) HINT percent difference = % 0

Solution

To approach the problem, we need to analyze and understand the following aspects:

  1. Given Information:

    • The table provides data for forces F1F_1 and F2F_2.
    • The resultant force RR is also given, along with the equilibrant.
  2. Force Analysis:

    • The resultant force RR is the vector sum of F1F_1 and F2F_2.
    • The equilibrant force F3F_3 is equal in magnitude but opposite in direction to RR. It balances the system.
  3. Data Summary:

ForceMass (kg)Force (N)Angle (degrees)x-component (N)y-component (N)
F1F_10.1501.4760°0.7351.273
F2F_20.1501.47300°0.735-1.273
R=F1+F2R = F_1 + F_2-1.471.470
F3F_3 (Equilibrant)-1.47180°-1.470
  1. Calculated Value for F3F_3:

    • Magnitude: F3,calc=1.47NF_{3,\text{calc}} = 1.47 \, \text{N}
    • Direction: θ3,calc=180\theta_{3,\text{calc}} = 180^\circ
  2. Experimental Value of F3F_3:

    • Magnitude: F3,exp=F_{3,\text{exp}} = (This value needs to be provided from experimental data.)
    • Direction: θ3,exp=\theta_{3,\text{exp}} = (This value also needs to be experimentally determined.)
  3. Percent Differences:

    • Magnitude Difference: Percent Difference=F3,expF3,calcF3,exp+F3,calc2×100\text{Percent Difference} = \frac{|F_{3,\text{exp}} - F_{3,\text{calc}}|}{\frac{F_{3,\text{exp}} + F_{3,\text{calc}}}{2}} \times 100

    • Angle Difference: Percent Difference=θ3,expθ3,calcθ3,exp+θ3,calc2×100\text{Percent Difference} = \frac{|\theta_{3,\text{exp}} - \theta_{3,\text{calc}}|}{\frac{\theta_{3,\text{exp}} + \theta_{3,\text{calc}}}{2}} \times 100

Completing the Table:

The missing experimental values and the percent differences can be filled in as follows:

  1. Magnitude F3,expF_{3,\text{exp}}: (Use the experimental measurement.)
  2. Angle θ3,exp\theta_{3,\text{exp}}: (Use the experimental measurement.)
  3. Percent Difference for Magnitude: Calculate using the formula.
  4. Percent Difference for Angle: Calculate using the formula.

Follow-up Questions:

  1. What are the x- and y-components of the resultant force RR?
  2. How would changing the mass affect the forces F1F_1 and F2F_2?
  3. Why is the direction of F3F_3 opposite to that of RR?
  4. How do experimental errors affect the calculation of F3F_3?
  5. What role does the angle play in determining the components of a vector?

Tip: Always double-check your calculations, especially when dealing with percent differences, as small changes can lead to significant percentage differences.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Vector Addition
Force Equilibrium
Trigonometry

Formulas

Vector components using trigonometric functions
Percent difference formula

Theorems

-

Suitable Grade Level

High School