Erin and Quin participated in a bake sale fundraiser for school. Erin made 72 pies and sold x pies. Quin baked 36 pies and sold half as many as Erin did.

How many pies did Erin sell if they each had the same number of pies left over?
A.72
B.36
C.24
D.18

We are given that:

- Erin made 72 pies and sold \( x \) pies.
- Quin made 36 pies and sold half as many pies as Erin did, which means Quin sold \( \frac{x}{2} \) pies.

The key condition is that both Erin and Quin had the same number of pies left over.

**Step 1: Write an equation for the pies left over for each person.**

- Erin’s remaining pies: \( 72 - x \).
- Quin’s remaining pies: \( 36 - \frac{x}{2} \).

Since they have the same number of pies left over, we set the two expressions equal to each other:
\[
72 - x = 36 - \frac{x}{2}
\]

**Step 2: Solve for \( x \).**

First, eliminate the fraction by multiplying the entire equation by 2:
\[
2(72 - x) = 2\left(36 - \frac{x}{2}\right)
\]
\[
144 - 2x = 72 - x
\]

Now, move all terms involving \( x \) to one side:
\[
144 - 72 = 2x - x
\]
\[
72 = x
\]

Thus, Erin sold \( x = 72 \) pies.

**Step 3: Verify the solution.**

- Erin sold 72 pies, so she had \( 72 - 72 = 0 \) pies left.
- Quin sold \( \frac{72}{2} = 36 \) pies, so she had \( 36 - 36 = 0 \) pies left.

Both Erin and Quin had 0 pies left, confirming the solution is correct.

**Answer: A. 72**

Would you like more details or have any questions?

Here are 5 related questions:
1. How would the equation change if Erin sold twice as many pies as Quin?
2. If Erin had made 100 pies instead of 72, how many pies would she sell under the same conditions?
3. What if Quin sold the same number of pies as Erin, how many pies would each have left?
4. How would the outcome change if Erin and Quin started with the same number of pies?
5. What happens if Quin sold a third of the pies Erin sold instead of half?

**Tip:** Always check your answer by substituting it back into the original equation to confirm it satisfies all conditions.

Erin and Quin participated in a bake sale fundraiser for school. Erin made 72 pies and sold x pies. Quin baked 36 pies and sold half as many as Erin did. How many pies did Erin sell if they each had the same number of pies left over? A.72 B.36 C.24 D.18

Learn how to solve a word problem involving Erin and Quin's bake sale, where Erin sold x pies and Quin sold half as many. The solution uses algebraic equations to find how many pies Erin sold, ensuring both had the same pies left. Perfect for students in Grades 6-8.

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