Math Problem Statement

I baked 440 apple pies and banana pies at first. I sold 3/4 of the apple pies and 2/5 of the banana pies. The number of banana pies unsold was twice the number of apple pies unsold. Which pies did I bake more at first and how many more?

Write the answer using model diagrams.

Solution

To solve the problem using model diagrams, we'll follow these steps:

  1. Define the Variables:

    • Let AA represent the total number of apple pies baked.
    • Let BB represent the total number of banana pies baked.
  2. Total Number of Pies:

    • We know the total number of pies baked is 440: A+B=440A + B = 440
  3. Sold and Unsold Pies:

    • 34\frac{3}{4} of the apple pies were sold. Therefore, 14\frac{1}{4} of the apple pies were unsold: Unsold Apple Pies=14A\text{Unsold Apple Pies} = \frac{1}{4}A
    • 25\frac{2}{5} of the banana pies were sold. Therefore, 35\frac{3}{5} of the banana pies were unsold: Unsold Banana Pies=35B\text{Unsold Banana Pies} = \frac{3}{5}B
  4. Relationship Between Unsold Pies:

    • The number of unsold banana pies is twice the number of unsold apple pies: 35B=2(14A)\frac{3}{5}B = 2 \left(\frac{1}{4}A\right) Simplify this equation: 35B=12A\frac{3}{5}B = \frac{1}{2}A Multiply both sides by 10 to clear the fractions: 6B=5A6B = 5A
  5. Solve the System of Equations:

    • We now have two equations: A+B=440A + B = 440 6B=5A6B = 5A
    • Solve the second equation for BB: B=56AB = \frac{5}{6}A
    • Substitute BB in the first equation: A+56A=440A + \frac{5}{6}A = 440 Combine like terms: 116A=440\frac{11}{6}A = 440 Multiply both sides by 611\frac{6}{11}: A=240A = 240
    • Substitute AA back into B=56AB = \frac{5}{6}A: B=56×240=200B = \frac{5}{6} \times 240 = 200
  6. Conclusion:

    • The number of apple pies baked at first is 240240.
    • The number of banana pies baked at first is 200200.

Therefore, more apple pies were baked initially, and the difference is: 240200=40240 - 200 = 40

Model Diagram Representation:

Total Pies Baked

440 pies\boxed{440 \text{ pies}}

Apple Pies

240 apple pies\boxed{240 \text{ apple pies}}

  • Sold: 34×240=180\frac{3}{4} \times 240 = 180
  • Unsold: 14×240=60\frac{1}{4} \times 240 = 60

Banana Pies

200 banana pies\boxed{200 \text{ banana pies}}

  • Sold: 25×200=80\frac{2}{5} \times 200 = 80
  • Unsold: 35×200=120\frac{3}{5} \times 200 = 120

The number of unsold banana pies (120) is twice the number of unsold apple pies (60), which confirms our solution.

Apple pies were baked more at first, and there were 40 more apple pies baked than banana pies.

Would you like more details or have any questions?

Relative Questions:

  1. What if the total number of pies baked was different? How would that change the solution?
  2. How would the problem change if the fractions of sold pies were different?
  3. What if the unsold ratio was different, such as three times instead of twice?
  4. How would you solve it if you only knew the difference in the number of pies baked?
  5. What if the number of pies sold was given in actual numbers instead of fractions?

Tip:

When solving word problems involving fractions and ratios, clearly define your variables and equations step-by-step to avoid confusion and ensure accuracy.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Equations
Fractions
Ratios

Formulas

A + B = 440 (Total pies equation)
Unsold Apple Pies = (1/4) * A
Unsold Banana Pies = (3/5) * B
Relationship between unsold pies: (3/5)B = 2 * (1/4)A
Solving system of equations: A + B = 440, 6B = 5A

Theorems

Systems of Linear Equations

Suitable Grade Level

Grades 7-9