Math Problem Statement

As part of an experiment, a scientist collected 2 samples of bacteria, A and B, each sample having 1,000 bacteria. The population of the bacteria increased by 10% per week in sample A, while it increased by 150 per week in sample B. Which statement is true? - In week 6, the number of bacteria in sample A is more than that in sample B. - The number of bacteria in sample A exceeded that in sample B for the first time in week 9. - The number of bacteria in sample B exceeded that in sample A for the first time in week 8. - The number of bacteria in sample A is 1,771 in week 7.

Solution

To determine which statement is true, let's analyze the growth of the bacteria in samples A and B over time.

Given:

  • Initial population in both samples A and B: 1,000 bacteria.
  • Growth rate for sample A: 10% per week.
  • Growth rate for sample B: 150 bacteria added per week.

Let's calculate the population for each sample week by week to verify the statements.

  1. Sample A (Exponential Growth): Each week, the population in sample A is multiplied by 1.10 (a 10% increase).

    • Formula: PopulationA=1000×(1.10)n\text{Population}_A = 1000 \times (1.10)^n, where nn is the number of weeks.
  2. Sample B (Linear Growth): Each week, 150 bacteria are added to the population in sample B.

    • Formula: PopulationB=1000+150×n\text{Population}_B = 1000 + 150 \times n, where nn is the number of weeks.

Now, let's calculate for each relevant week to check each statement:

Week-by-Week Calculations

Week 6:

  • Sample A: 1000×(1.10)617711000 \times (1.10)^6 \approx 1771
  • Sample B: 1000+150×6=19001000 + 150 \times 6 = 1900

Week 7:

  • Sample A: 1000×(1.10)719481000 \times (1.10)^7 \approx 1948
  • Sample B: 1000+150×7=20501000 + 150 \times 7 = 2050

Week 8:

  • Sample A: 1000×(1.10)821431000 \times (1.10)^8 \approx 2143
  • Sample B: 1000+150×8=22001000 + 150 \times 8 = 2200

Week 9:

  • Sample A: 1000×(1.10)923581000 \times (1.10)^9 \approx 2358
  • Sample B: 1000+150×9=23501000 + 150 \times 9 = 2350

Analysis of Statements

  1. In week 6, the number of bacteria in sample A is more than that in sample B.

    • False: Sample A has 1771 bacteria, and Sample B has 1900 in week 6. Sample B has more bacteria.
  2. The number of bacteria in sample A exceeded that in sample B for the first time in week 9.

    • True: In week 9, Sample A has 2358 bacteria, and Sample B has 2350. This is the first time Sample A exceeds Sample B.
  3. The number of bacteria in sample B exceeded that in sample A for the first time in week 8.

    • False: Sample B has been greater than Sample A from the start up until week 8.
  4. The number of bacteria in sample A is 1,771 in week 7.

    • False: The population in Sample A is approximately 1,771 in week 6, not week 7.

Conclusion

The correct answer is:

  • The number of bacteria in sample A exceeded that in sample B for the first time in week 9.

Would you like further details on any of these calculations?


Here are 5 related questions for practice:

  1. What would be the population of each sample at week 10?
  2. How many weeks would it take for Sample A to double its initial population?
  3. At what week will Sample A's population be approximately 3000?
  4. What is the difference in population between the two samples at week 12?
  5. How would the calculations change if Sample B's weekly increase was instead a 20% growth?

Tip: For exponential growth calculations, understanding the compound growth formula is essential for accuracy.

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Math Problem Analysis

Mathematical Concepts

Exponential Growth
Linear Growth
Population Dynamics

Formulas

Exponential Growth Formula for Sample A: Population_A = 1000 * (1.10)^n
Linear Growth Formula for Sample B: Population_B = 1000 + 150 * n

Theorems

Exponential Growth Theory
Linear Growth Calculation

Suitable Grade Level

Grades 9-12