Math Problem Statement

A swimmer swims from the beginning of a pool of length L once during the time interval from 0 to t1, covering the length of the pool at an average speed of v1 and then returns. During the interval t1 to t2, the swimmer covers the pool's length with an average speed of v2. What is the average speed of the swimmer during the interval 0 to t2?

Solution

The text is in Persian. Here's its transcription and translation before analyzing the problem:

Transcription:

شناگری از ابتدای استخر به طول L یک بار در بازۀ زمانی صفر تا t۱ طول استخر را با تندی متوسط v۱ رفته و برمی‌گردد و در بازۀ زمانی t۱ تا t۲ طول استخر را با تندی متوسط v۲ طی می‌کند. در بازۀ زمانی صفر تا t۲، اندازۀ سرعت متوسط شناگر کدام است؟

Translation:

A swimmer swims from the beginning of a pool of length LL once during the time interval from 00 to t1t_1, covering the length of the pool at an average speed of v1v_1 and then returns. During the interval t1t_1 to t2t_2, the swimmer covers the pool's length with an average speed of v2v_2. What is the average speed of the swimmer during the interval 00 to t2t_2?


Solution:

To solve this problem, we need to compute the average speed over the entire time interval 00 to t2t_2.

Step 1: Total Distance

  1. From 00 to t1t_1: The swimmer swims the pool's length LL back and forth, so the total distance covered is: d1=2Ld_1 = 2L
  2. From t1t_1 to t2t_2: The swimmer swims the pool's length LL one way, so the distance covered is: d2=Ld_2 = L
  3. Total distance: dtotal=d1+d2=2L+L=3Ld_{\text{total}} = d_1 + d_2 = 2L + L = 3L

Step 2: Total Time

  1. From 00 to t1t_1: The time taken is t1t_1.
  2. From t1t_1 to t2t_2: The time taken is t2t1t_2 - t_1.
  3. Total time: ttotal=t1+(t2t1)=t2t_{\text{total}} = t_1 + (t_2 - t_1) = t_2

Step 3: Average Speed

Average speed is defined as: vavg=Total DistanceTotal Timev_{\text{avg}} = \frac{\text{Total Distance}}{\text{Total Time}} Substitute the values: vavg=3Lt2v_{\text{avg}} = \frac{3L}{t_2}


Final Answer:

The swimmer's average speed over the interval 00 to t2t_2 is: vavg=3Lt2v_{\text{avg}} = \frac{3L}{t_2}


Do you need further clarifications or detailed examples?

Here are 5 related questions for practice:

  1. How would the average speed change if v2v_2 were double v1v_1?
  2. What happens to the average speed if t1=t2t_1 = t_2?
  3. How is the calculation affected if the swimmer's return distance had a different speed?
  4. How can we calculate the swimmer's average velocity instead of average speed?
  5. If L=50L = 50 meters, t1=20t_1 = 20 seconds, and t2=40t_2 = 40 seconds, what is the numerical value of vavgv_{\text{avg}}?

Tip: Average speed depends only on total distance and total time, not the speeds during individual intervals.

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Math Problem Analysis

Mathematical Concepts

Average Speed
Distance and Time Calculations

Formulas

Average speed = Total distance / Total time
Total distance = Distance covered in interval 1 + Distance covered in interval 2
Total time = Time in interval 1 + Time in interval 2

Theorems

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Suitable Grade Level

Grades 8-10