The question asks to find the average rate of change of the function $g(t)$ on the interval $[0, 3]$.

Steps to solve:

1. Identify the points from the graph at $t = 0$ and $t = 3$:

   • From the graph, at $t = 0$, $g(0) = 1$.
   • At $t = 3$, $g(3) = 4$.

2. Use the formula for average rate of change: $\text{Average Rate of Change} = \frac{g(3) - g(0)}{3 - 0}$ Substituting the values: $\frac{4 - 1}{3 - 0} = \frac{3}{3} = 1$

Thus, the average rate of change of $g(t)$ on the interval $[0, 3]$ is 1.

Would you like more details or have any questions?

Here are 5 related questions:

1. How does the average rate of change relate to the slope of a secant line?
2. How would you compute the average rate of change for a different interval, say $[1, 4]$?
3. What is the interpretation of the average rate of change in practical terms?
4. How would you determine whether the function is increasing or decreasing based on the rate of change?
5. How can you find the instantaneous rate of change at a point on the graph?

Tip: The average rate of change is essentially the slope of the line connecting two points on the graph.