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To solve this problem, we need to calculate the average force exerted on Superman's chest by the stream of bullets bouncing off his chest without any change in speed.

### Given Data:
- Mass of each bullet, \( m = 5.7 \, \text{g} = 0.0057 \, \text{kg} \) (converted to kilograms).
- Rate of bullets fired, \( R = 180 \, \text{bullets/min} \).
- Speed of each bullet, \( v = 490 \, \text{m/s} \).
- Since the bullets bounce back with no change in speed, the change in velocity for each bullet is \( \Delta v = 2v = 2 \times 490 = 980 \, \text{m/s} \).

### Steps:

1. **Convert the rate of fire to bullets per second**:
   \[
   R = \frac{180 \, \text{bullets}}{60 \, \text{seconds}} = 3 \, \text{bullets/second}
   \]

2. **Calculate the change in momentum (\( \Delta p \)) for each bullet**:
   - The change in momentum when a bullet rebounds is:
     \[
     \Delta p = m \cdot \Delta v = 0.0057 \, \text{kg} \times 980 \, \text{m/s} = 5.586 \, \text{kg} \cdot \text{m/s}
     \]

3. **Calculate the total force (\( F \)) exerted on Superman’s chest**:
   - The force is the rate of change of momentum, which is the momentum change per bullet times the rate of fire:
     \[
     F = \Delta p \times R = 5.586 \, \text{kg} \cdot \text{m/s} \times 3 \, \text{bullets/second} = 16.758 \, \text{N}
     \]

### Answer:
The magnitude of the average force on Superman's chest from the stream of bullets is approximately:
\[
F \approx 16.76 \, \text{N}
\]

Would you like more details on any step or have additional questions?

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Here are some related questions for further exploration:

1. How would the force change if the rate of bullets increased to 300 bullets per minute?
2. What if the speed of each bullet were doubled?
3. How does this type of force calculation relate to Newton’s Third Law of Motion?
4. How would the answer change if the bullets didn’t bounce back and instead embedded into Superman’s chest (hypothetically)?
5. How would air resistance affect the force, if at all?

**Tip:** Remember, in momentum problems, bouncing back (rebound) effectively doubles the speed change, significantly impacting the resulting force.

It is well known that bullets and other missiles fired at Superman simply bounce off his chest. Suppose that a gangster sprays Superman's chest with 5.7 g bullets at the rate of 180 bullets/min, and the speed of each bullet is 490 m/s. Suppose too that the bullets rebound straight back with no change in speed. What is the magnitude of the average force on Superman's chest from the stream of bullets?

Learn how to calculate the average force on Superman's chest as bullets bounce off with a speed of 490 m/s and a rate of 180 bullets per minute. This problem uses concepts of momentum and impulse, with step-by-step solutions suitable for high school physics students.

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