The problem shown in the image reads:

"A 17.2-g bullet is fired from a rifle. It takes 2.12 × 10⁻³ s for the bullet to travel the length of the barrel, and it exits the barrel with a speed of 718 m/s. Assuming that the acceleration of the bullet is constant, find the average net force exerted on the bullet."

Let's solve this problem step by step.

Step 1: Convert mass to kilograms

The mass $m$ of the bullet is given as 17.2 g. Convert this to kilograms: $m = 17.2 \, \text{g} = 0.0172 \, \text{kg}$

Step 2: Find the acceleration of the bullet

We are given the final velocity $v_f = 718 \, \text{m/s}$, the initial velocity $v_i = 0 \, \text{m/s}$ (since the bullet starts from rest), and the time $t = 2.12 \times 10^{-3} \, \text{s}$. Using the equation for acceleration: $a = \frac{v_f - v_i}{t}$ Substitute the values: $a = \frac{718 \, \text{m/s} - 0 \, \text{m/s}}{2.12 \times 10^{-3} \, \text{s}} = \frac{718}{0.00212}$

Step 3: Calculate the average force

The average net force $F$ exerted on the bullet is given by Newton's second law: $F = m \cdot a$

Now, let's calculate the values for $a$ and $F$.### Step 2: Acceleration Calculation The acceleration of the bullet is approximately: $a = 338,679.25 \, \text{m/s}^2$

Step 3: Force Calculation

The average net force exerted on the bullet is approximately: $F = 5825.28 \, \text{N}$

Would you like a detailed explanation of any part of this solution or more questions related to this topic? Here are five related questions to deepen your understanding:

1. How would the force change if the mass of the bullet were doubled?
2. What would happen to the acceleration if the time taken to travel through the barrel were halved?
3. How can we calculate the work done on the bullet by the force?
4. How does Newton's second law apply to this scenario?
5. How would air resistance affect the motion of the bullet after it exits the barrel?

Tip: Always convert units to SI (meters, kilograms, seconds) to ensure consistency when applying formulas in physics.