Math Problem Statement

  1. Let m and n be positive integers. Exhibit an arrangement of the integersbetween 1 and mn which has no increasing subsequence of length m + 1,and no decreasing subsequence of length n + 1

Solution

This problem is asking for an arrangement of integers between 11 and mnmn such that there is no increasing subsequence of length m+1m+1 and no decreasing subsequence of length n+1n+1. A well-known solution to this problem is based on the Robinson-Schensted-Knuth (RSK) correspondence and the construction of a standard Young tableau. Here’s a construction for such a sequence:

Solution Approach:

One common method to find such a sequence is to use a permutation that avoids long increasing or decreasing subsequences. The Ferrer diagram and the RSK algorithm ensure that there are bounds on the lengths of the increasing and decreasing subsequences.

We can use a two-line standard representation approach, which helps control both the increasing and decreasing subsequences. Specifically, the reverse row-reading word of an m×nm \times n tableau provides such a sequence.

Construction:

An arrangement that satisfies the conditions for this problem can be obtained using the Lexicographic order of the integers organized into an m×nm \times n grid.

For simplicity, we can take the following example construction when m=3m = 3 and n=3n = 3 (though the method works for any mm and nn):

  1. List the integers between 11 and mn=9mn = 9. 1,2,3,4,5,6,7,8,91, 2, 3, 4, 5, 6, 7, 8, 9

  2. Arrange these integers in a grid as

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Permutation Theory
Young Tableaux
RSK Correspondence

Formulas

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Theorems

Robinson-Schensted-Knuth Correspondence
Ferrer Diagram

Suitable Grade Level

Undergraduate/Advanced High School